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Does string.format is more efficient than append to string using '+'


Does string.format is more efficient than append to string using '+'

By : user2949620
Date : November 17 2020, 01:00 AM
I wish did fix the issue. Appending using operators is generally more efficient. Format has to take the string and find "%"'s and so, and replace them with corresponding values. Appending is simpler, and shorter to type!
Imagine you are the compiler.
code :


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Is chain of StringBuilder.append more efficient than string concatenation?

Is chain of StringBuilder.append more efficient than string concatenation?


By : Bart E
Date : March 29 2020, 07:55 AM
To fix this issue You have to balance readability with functionality.
Let's say you have the following:
code :
String str = "foo";
str += "bar";
if(baz) str += "baz";
StringBuilder strBuilder = new StringBuilder("foo");
strBuilder.append("bar");
if(baz) strBuilder.append("baz");
String str = strBuilder.toString();
public String concat(String s1, String s2, String s3) {
    return s1 + s2 + s3;
}
public String concat(String s1, String s2, String s3) {
    StringBuffer sb = new StringBuffer();
    sb.append(s1);
    sb.append(s2);
    sb.append(s3);
    return sb.toString();
}
return s1 + s2 + s3;
return new StringBuilder().append(s1).append(s2).append(s3).toString();
Most efficient way to append a constant string to a variable string in Java?

Most efficient way to append a constant string to a variable string in Java?


By : Kknewkles
Date : March 29 2020, 07:55 AM
I hope this helps . A performant way to do this is to use a StringBuilder to concatenate your string:
code :
StringBuilder builder = new StringBuilder();
for(int i = 0; i < count; i++){
    builder.append(x.charAt(i));
    builder.append(x.charAt(i>>4));
    builder.append(x.charAt(i>>8));
}

return builder.toString();
StringBuilder builder = new StringBuilder();
for(int i = 0; i < count; i++){
    builder.append(x);
}

return builder.toString();
C# Full-text search string format : string remove all adjacent duplicates and append with 'AND' 'OR'

C# Full-text search string format : string remove all adjacent duplicates and append with 'AND' 'OR'


By : user2737449
Date : March 29 2020, 07:55 AM
I hope this helps . Since you haven't shown what you've done so far I'm assuming that you haven't started on a solution, so here's a high level algorithm:
In that case, use String.Split(' ') to split the searchstring by each space.
code :
    if (output.Contains(" ") && !output.Contains("and") && !output.Contains("or"))
    {
        return string.Join(" or ", output.Split(' ').Select(I => I.Trim()));
    }
            foreach (var item in strArray)
            {
                currStr = item.Trim();
                keywordFlag = searchKeywords.Contains(prevStr) && searchKeywords.Contains(currStr);
                duplicateFlag = outputArray.Contains(currStr) && !searchKeywords.Contains(currStr);
                if (!currStr.Equals(prevStr) && !keywordFlag && !duplicateFlag)
                {
                    if (!searchKeywords.Contains(prevStr) && !searchKeywords.Contains(currStr) && prevStr != "")
                    {
                        outputArray.Add("or");
                    }
                    outputArray.Add(currStr);
                    prevStr = currStr;
                }
            }
            if (outputArray.Count() == 2)
            {
                if(searchKeywords.Contains(outputArray[0]))
                    outputArray.Remove(outputArray[0]);
                else if(searchKeywords.Contains(outputArray[1]))
                    outputArray.Remove(outputArray[1]);
            }
An efficient way to prepend a string to another format string using vsprintf

An efficient way to prepend a string to another format string using vsprintf


By : FrexxY
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I am using vsprintf to generate a string from a format and need to prepend a looked up prepend string before logging it. The code below prints the format string but how would I prepend another string to that? Ideally in a fairly efficient way. , You could try:-
code :
strcpy (buffer, chaTypes [id]);
vsprintf (&buffer [strlen (buffer)], format, args);
static int [] lengths = null;

if (lengths == null)
{
  lengths = malloc (sizeof (int), sizeof chaTypes / sizeof chaTypes [0]);
  foreach string
    lengths [i] = strlen (chaTypes [i]);
}
How do I append an other string in string.format() method dynamically!

How do I append an other string in string.format() method dynamically!


By : sunkanmi
Date : March 29 2020, 07:55 AM
To fix this issue Use the StringBuilder class to concatenate strings. This is the preferred way to build strings.
Refer here: http://download.oracle.com/javase/tutorial/java/data/buffers.html
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