How to slice find result with php and mongo?

How to slice find result with php and mongo?

By : Ido
Date : November 17 2020, 01:00 AM
I hope this helps . Here is a simplest/minimal example of pagination. I am showing you only the code you are struggling with. This is not a complete working pagination code. Rest of it you can write yourself I guess.
code :
$skip_results = (int)($results_per_page * ($page_number - 1));
$cursor = $collection->find($query)->limit($results_per_page)->skip($skip_results);

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In String.prototype.slice(), should .slice(0,-0) and .slice(0,+0) output the same result?

In String.prototype.slice(), should .slice(0,-0) and .slice(0,+0) output the same result?

By : Brendan Johnson
Date : March 29 2020, 07:55 AM
I wish did fix the issue. From a mathematical perspective there is no negative zero. Positive is any number greater than zero, and negative is any number smaller than zero. Zero is neither of those. So I guess the behaviour you described is correct.
code :
var counter = 1;
var myText = counter + " unit" + (counter > 1 ? "s" : "");
Mongo Aggregate find element in array based on match/sort/slice/group query

Mongo Aggregate find element in array based on match/sort/slice/group query

By : Aad Wildeboer
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You can try below aggregation.
Added two groups one group each for count by type and other for count by user.
code :
  {"$match":{"createdDate":{"$gte":"2018-01-01 00:00:00","$lte":"2018-03-02 23:59:59"}}},
  {"$match":{"visits.date":{"$gte":"2018-01-01 00:00:00","$lte":"2018-03-02 23:59:59"}}},
Is there a way to get slice as result of Find()?

Is there a way to get slice as result of Find()?

By : T. Doğan
Date : March 29 2020, 07:55 AM
wish helps you The result of a MongoDB find() is always a list of documents. So if you want a list of values, you have to convert it manually just as you did.
Using a custom type (derived from string)
code :
type Username string

func (u *Username) SetBSON(raw bson.Raw) (err error) {
    doc := bson.M{}
    if err = raw.Unmarshal(&doc); err != nil {
    *u = Username(doc["username"].(string))
c := mongodb.DB("mybase").C("mycollection") // Obtain collection

var uns []Username
err = c.Find(nil).Select(bson.M{"username": 1, "_id": 0}).All(&uns)
if err != nil {
var uns []string
it := c.Find(nil).Select(bson.M{"username": 1, "_id": 0}).Iter()
defer it.Close()
for doc := (bson.M{}); it.Next(&doc); {
    uns = append(uns, doc["username"].(string))
if err := it.Err(); err != nil {
Mongo db query find doesn't show array result

Mongo db query find doesn't show array result

By : James Carter
Date : March 29 2020, 07:55 AM
this will help So the issue is with where you are initializing your array, put it before your find. I edited your code, take a look at it.
Also your main issue is farms is an array therefore farms._id doesn't exist. find finds an array if you want to find only 1 then you use findOne
code :
router.post('/login', function(req, res) {
User.findOne({ username: req.body.username}, function(err, user) {
    if (err){
        return res.status(500).send('Error on the server.');
    if (!user){
        return res.status(401).send({status: 'ko', error: {msg: 'The username ' + req.body.username + ' is not associated with any account.'}});
    var passwordIsValid = bcrypt.compareSync(req.body.password, user.password);
    //if (!passwordIsValid) return res.status(401).send({ auth: false, token: null });
    if (!passwordIsValid){
        return res.status(401).send({status: 'ko', error: {msg:'Authentication failed. Wrong password.',auth: false, token: null}});
    // Make sure the user has been verified
    if (!user.isVerified){
        return res.status(401).send({status: 'ko', error: {type: 'not-verified', msg: 'Your account has not been verified.'}});
    if (!user.statusUser){
        return res.status(401).send({status: 'ko', error: {msg: 'The username ' + req.body.username + ' is blocked by Admin'}});
    // if user is found and password is valid
    // create a token
    var token = jwt.sign({ id: user._id }, config.secret, {
      expiresIn: 86400 // expires in 24 hours

    // inserimento farm id //
    Farm.find({ farmId: user.farmId}, (err, farms) => {
        var identify_farm = [];

           if (farm) {

    // inserimento farm id //

    // return the information including token as JSON
    req.session.user = user;
    res.status(200).send({status: 'ok', data: {auth: true, token: token, farmId: user.farmId, roles: user.roles, id_utente: user._id, identify_farms: identify_farm}});
Mongo DB aggregate - keep results even if match didn't find result

Mongo DB aggregate - keep results even if match didn't find result

By : pixius
Date : March 29 2020, 07:55 AM
With these it helps You could do that by using $addFields & $cond which conditionally adds same field Varas or null, So add this stage as last stage to your existing pipeline :
code :
{$addFields : {Varas: { $cond: [ {$eq : ['$Varas.CodVara', '9001']}, '$Varas', null ] }}}
        $match: {
            Cod: '5'
        $unwind: '$Orgaos'
        $match: {
            'Orgaos.Siglas': 'MS'
        $lookup: {
            'from': 'Varas',
            'localField': 'Orgaos.Varas',
            'foreignField': '_id',
            'as': 'Varas'
        $unwind: '$Varas'
    }, { $addFields: { Varas: { $cond: [{ $eq: ['$Varas.CodVara', '9001'] }, '$Varas', null] } } }
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