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Generating a Cross Product from two input schemas using BizTalk Map


Generating a Cross Product from two input schemas using BizTalk Map

By : Hadi
Date : November 17 2020, 01:00 AM
should help you out I tried various combinations of functoids to get the required output schema, but nothing worked. So, I finally moved on to use scripting functoid, which served my purpose. I am posting my finding as it could be helpful to someone else.
This is how I proceeded:
code :
<xsl:template name="Template1">
    <xsl:param name="MessagePart_0_Xml" /> <!--Not used anywhere-->
    <xsl:variable name="Msg_0_RootNode" select="/*[local-name()='Root']/*[local-name()='InputMessagePart_0']/*[local-name()='Root']" />
    <xsl:variable name="Msg_1_RootNode" select="/*[local-name()='Root']/*[local-name()='InputMessagePart_1']/*[local-name()='Root']" />
    <xsl:for-each select="$Msg_0_RootNode/Data">
        <xsl:variable name="Msg_0_DataNode" select="." />
        <xsl:for-each select="$Msg_1_RootNode/Data">
	        <xsl:variable name="Msg_1_DataNode" select="." />
	        <xsl:if test="$Msg_0_DataNode/ItemCode/text() = $CostCenterDataNode/Code/text()">
	            <ItemCost>
	                <xsl:value-of select="$Msg_0_DataNode/ItemCost/text()" />
                </ItemCost>
	            <ShipAddr>
                    <xsl:value-of select="$CostCenterDataNode/ShipAddr/text()" />
	            </ShipAddr>
            </xsl:if>
        </xsl:for-each>
    </xsl:for-each>
</xsl:template>


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BizTalk 2009 Community ODBC Adapter - Generating Schemas from MySQL Stored Procedure

BizTalk 2009 Community ODBC Adapter - Generating Schemas from MySQL Stored Procedure


By : omi
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have now figured out how to use the ODBC Adpater with a MySQL stored procedure that has parameters.
The key to this is not selecting the stored procedure option and instead using the SQL Script option.
Merge 2 input XML schemas into one CSV file - biztalk 2009

Merge 2 input XML schemas into one CSV file - biztalk 2009


By : Ed Y.
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You will also need
1) To have a schema with the 10 fields that is defined as a Flat File Schema (Add new Item, Flat File Schema), in which you define child delimiter on the root with Child Delimiter Type Hexadecimal and the Child Delimiter as 0x0D 0x0A (Carriage Return, Line Feed). Then on the record you must set the Child Delimiter Type Character and the Child Delimiter as , (comma). You may also want to set the Wrap Character to " on the fields if you expect any commas in your data.
Generating a row within a cross product given an integer

Generating a row within a cross product given an integer


By : Twisted Candle
Date : March 29 2020, 07:55 AM
With these it helps Induction is your friend when looking for solutions to this kind of problem.
For the easy case, it looks like
code :
easy( a, i ) ≡ easyHelper( a, a.length, i )  
easyHelper( a, n, i ) ≡ easyInduction( easyHelper, 0 )( a, n, i )

easyInduction( f, b )( a, 0, 0 ) ≡ []  
easyInduction( f, b )( a, 0, i + 1 ) ≡ undefined
easyInduction( f, b )( a, n + 1, i ) ≡
   let t = a[n + 1].length - b
    in f( a, n, ⌊i / t⌋ ) ++ [ a[n + 1][i mod t] ]
hard( a, i ) ≡ hardHelper( a, a.length ).second( i )
hardHelper( a, 0 ) ≡ ( 1, { case 0 => [] } )
hardHelper( a, n + 1 ) ≡
  let t = a[n + 1].length
  and ( k, f ) = hardHelper( a, n )
  and k' = k * ( t - 1 )
  and f'( i ) =
        if ( i < k' )
        then easyInduction( f, 1 )( a, n + 1, i )
        else if ( k' <= i < k' + k )
        then easyInduction( f, 1 )( a[ 0..n ] ++ [ [ null ] ], n + 1, i - k' )
        else easyInduction( ( b, m, j ) => f( b, m, j + k ), 0 )( a, n + 1, i - k' - k )
   in ( k', f' )
generating cross product for list of lists

generating cross product for list of lists


By : gan
Date : March 29 2020, 07:55 AM
I wish this helpful for you What you want is a carthesian product. itertools has a function product that does exactly that:
code :
import itertools
a = [[1, 2, 3], [4, 5], [3], [1]]
p = itertools.product(*a)
print list(p)
[(1, 4, 3, 1),
 (1, 5, 3, 1),
 (2, 4, 3, 1),
 (2, 5, 3, 1),
 (3, 4, 3, 1),
 (3, 5, 3, 1)]
Edifact D16 XML schemas for use in BizTalk 2016

Edifact D16 XML schemas for use in BizTalk 2016


By : Cyber Army
Date : March 29 2020, 07:55 AM
will be helpful for those in need To be clear, what you are planning is not uncommon.
This has been the solution for odd versions in both EDIFACT and X12 for ever.
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