logo
down
shadow

List of functions with duplicates


List of functions with duplicates

By : user2949229
Date : November 16 2020, 06:23 AM
this will help Generically, there's no way of knowing whether two functions are equal. Even if you were looking at two copies of the same function instance, they might invoke some side effect (e.g. generating a random number) so it would be incorrect in some sense to elide the second call. In the cases where the function provably doesn't have side effects, the JVM can probably figure that out for itself. So I honestly think you're solving the wrong problem here.
But if you really want to memoize, I'd use scalaz Memo. The different kinds of Memo document what thread safety guarantees they offer.
code :
def execute(fs: List[() => Int]) = {
  val m = Memo.mutableHashMapMemo({f: (() => Int) => f()})
  fs map m
}


Share : facebook icon twitter icon
Weeding duplicates from a list of functions

Weeding duplicates from a list of functions


By : oearrsdd
Date : March 29 2020, 07:55 AM
To fix this issue No, this is not possible. Functions cannot be compared for equality.
The reason for this is:
code :
data Function = AddTwo | Double | Square deriving Eq

call AddTwo  =  (+2)
call Double  =  (*2)
call Square  =  (^2)
How to remove duplicates from comma separated list by regex in Oracle but I don't want duplicates values?

How to remove duplicates from comma separated list by regex in Oracle but I don't want duplicates values?


By : user7864467
Date : March 29 2020, 07:55 AM
This might help you Try this, as per article http://www.dba-oracle.com/t_extract_comma_delimited_strings_oracle_sql.html:
code :
select distinct str from
(select regexp_substr ('ABCD1234, XYZ, ABCD1234, ABCD1234C, ABCD1234, abc, abcX, 1234U, 1234', '[^, ]+',1, rownum) str 
from dual 
connect by level <= regexp_count ('ABCD1234, XYZ, ABCD1234, ABCD1234C, ABCD1234, abc, abcX, 1234U, 1234', '[^, ]+')) v;
Duplicates at index[0] of tuples within a list, comparing a value of the duplicates, returning list of duplicates with t

Duplicates at index[0] of tuples within a list, comparing a value of the duplicates, returning list of duplicates with t


By : enkidupal
Date : March 29 2020, 07:55 AM
This might help you I currently have a list of tuples, with the following syntax: , Using itertools.groupby()
code :
from itertools import groupby
List = [(22, 0, 40.210), (23, 0, 43.193), (23, 1, 80.867), 
        (40, -1, 32.159), (40, 0, 50.408)]

groups = [list(g) for _,g in groupby(sorted(List), key=lambda t:t[0])]
x = [min(g, key=lambda t:t[2]) for g in groups if len(g) > 1]
[(23, 0, 43.193), (40, -1, 32.159)]
How to remove all the duplicates in a list using scheme (only abstract list functions allowed)

How to remove all the duplicates in a list using scheme (only abstract list functions allowed)


By : Alec
Date : March 29 2020, 07:55 AM
Any of those help It's possible to use foldr for this, the trick is knowing what to write in the lambda:
list allows duplicates but how to write logic to dis-allow duplicates in list in core java

list allows duplicates but how to write logic to dis-allow duplicates in list in core java


By : enerdo
Date : March 29 2020, 07:55 AM
Does that help The easiest way is to use a LinkdHashSet instead. It will prevent duplicates, and you can still iterate over the elements in the same order they were added to the Set.
shadow
Privacy Policy - Terms - Contact Us © ourworld-yourmove.org