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YEAR() fitting to WEEKNUM(...,21) in Excel


YEAR() fitting to WEEKNUM(...,21) in Excel

By : user2949221
Date : November 16 2020, 06:23 AM
I wish did fix the issue. The "Year" of the week is determined by the year of the Thursday of that week (assuming ISO week numbers) so you can just find the Thursday and then get the year of that date, i.e. for any date in A1
=YEAR(A1-WEEKDAY(A1,3)+3)
code :


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Get week starting date from weeknum and year in R

Get week starting date from weeknum and year in R


By : user3784018
Date : March 29 2020, 07:55 AM
I wish this helpful for you I'm looking for a function that will get year + week number + Week day, and return a date, for example: , Using strptime:
code :
strptime("2015Monday23", "%Y%A%U")
# [1] "2015-06-08"
strptime(paste0(2015, "Monday", 23), "%Y%A%U")
Weeknum that doesn't start from 1st every year

Weeknum that doesn't start from 1st every year


By : Jessica Laura Sendal
Date : October 28 2020, 07:41 AM
Hope this helps How can i start weeknum from first week in 2018 and go on through 2019, 2020, 2021, 2022... without starting the count from 1 every year. Ex: if 2018 has 44 weeks i want the weeknum(1-1-2019) to return 45 not 1 and so on. , If you Week starts on Monday use:
code :
=INT((A1-"1/1/2018")/7)+1
=INT((A1-"1/1/2018"+1)/7)+1
DAX WeekNum for more than 1-year?

DAX WeekNum for more than 1-year?


By : codestorm
Date : March 29 2020, 07:55 AM
seems to work fine You could concatenate your YEAR() and WEEKNUM() results in a single column like this:
code :
WeekNum =
CONCATENATE ( WEEKNUM ( 'Calendar'[Date] ), YEAR ( 'Calendar'[Date] ) )
WeekNum =
CONCATENATE (
    WEEKNUM ( 'Calendar'[Date] ),
    CONCATENATE ( " - ", YEAR ( 'Calendar'[Date] ) )
)
Oracle - How to get date from YEAR, WEEKNUM and WEEKDAY?

Oracle - How to get date from YEAR, WEEKNUM and WEEKDAY?


By : Joyce
Date : March 29 2020, 07:55 AM
hope this fix your issue I think there is no built-in function for this, you will have to build one on your own. below is one of the solutions you can make use of.
code :
WITH FUNCTION getDate(p_year IN NUMBER, p_weeks IN NUMBER, p_day in NUMBER) RETURN DATE
IS
  v_tmp date;
  v_day number;
BEGIN
  v_tmp := to_date('01/01/'||to_char(p_year),'dd/mm/yyyy'); 
  v_day := to_char(v_tmp,'D');

  RETURN v_tmp+(p_weeks-1)*7+p_day-(v_day)+1;
END;
SELECT getDate(2019,22,2)
FROM DUAL;
/
How to rollover WeekNum If year does not start on a specific weekday (Like Friday)

How to rollover WeekNum If year does not start on a specific weekday (Like Friday)


By : user3555179
Date : March 29 2020, 07:55 AM
Does that help I figured out a way to achieve my end result. But I know there is still better way to do same thing and hence I am keeping this question open for better approach.
Here is what I did: 1. Retrieve MONTH, DAY and WEEKDAY from given date
code :
Range("AW5:AW" & FilterDataLastRow).Formula = "=MONTH(RC[6])"
Range("AX5:AX" & FilterDataLastRow).Formula = "=DAY(RC[5])"
Range("AY5:AY" & FilterDataLastRow).Formula = "=WEEKDAY(RC[4],16)"
For i = 5 To FilterDataLastRow
' Check for records with Month = 1 And DAY is 1-6 and WEEKDAY < 6
    If Range("AW" & i).Value = 1 And Range("AX" & i).Value < 7 Then
          CurrYear = Year(Range("BC" & i).Value)
          PrevYear = CurrYear - 1
          PrevYearLastDay = "12/31/" & PrevYear
          Range("AV" & i).Value = PrevYearLastDay
'Get the Day of Weel on 31st December of Previous Year
          Range("AU" & i).Value = "=WEEKDAY(RC[1],16)"
'Calculate Number of Days remaining for new week to start
          DaysRemForNewWeek = 8 - Range("AU" & i).Value
'Calculate Date of First Friday of Current Year
          Range("AT" & i).Value = PrevYearLastDay + DaysRemForNewWeek
'Compare all the dates prior to first Friday and rollover WeekNum from last year for these dates
          If Range("BC" & i).Value < Range("AT" & i).Value Then
                    Range("AZ" & i).Formula = "=(TEXT(RC[-4],""yyyy""))&(TEXT(WEEKNUM(RC[-4],16),""00""))"
            Else
                    Range("AZ" & i).Formula = "=(TEXT(RC[3],""yyyy""))&(TEXT(WEEKNUM(RC[3],16),""00""))"
        End If
    Else
          Range("AZ" & i).Formula = "=(TEXT(RC[3],""yyyy""))&(TEXT(WEEKNUM(RC[3],16),""00""))"
    End If
Next i
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