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what is missing in my java regex?


what is missing in my java regex?

By : FinsterDarwin
Date : November 16 2020, 06:23 AM
Hope this helps I want to fetch , Why use a regular expression to begin with?
Given
code :
final String s = "url(http://d1oiazdc2hzjcz.cloudfront.net/promotions/precious/2x/p_608_o_6288_precious_image_1419866866.png)";


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Java regex missing values

Java regex missing values


By : DevXDan
Date : March 29 2020, 07:55 AM
With these it helps A cleaner regex is [*]{3}\d+[*]{3}. Check it against the following to see how it goes:
code :
final Pattern pattern = Pattern.compile("[*]{3}\\d+[*]{3}");
final Matcher matcher = pattern.matcher("inputfile");
while (matcher.find())
{
  System.out.println(matcher.group());
}
Is regex from Java buggy or am i missing something?

Is regex from Java buggy or am i missing something?


By : JoSchmoe
Date : March 29 2020, 07:55 AM
hop of those help? With this regex : , Why don't you just remove the parenthesis and split around the comma?
code :
import org.apache.commons.lang3.StringUtils;
...
theString = StringUtils.strip(theString,"()"));
String[] tokens = theString.split(",");
Double number2 = Double.parse(tokens[1]);
What am i missing in this java regex for netbeans replace

What am i missing in this java regex for netbeans replace


By : MadRussianHacker
Date : March 29 2020, 07:55 AM
this will help If I've understood your question, I'd use 2 different replacement operations, one to remove '',true and another to remove ,true.
deleting '', true
Regex in java keeps on missing data

Regex in java keeps on missing data


By : Haziz Senon
Date : March 29 2020, 07:55 AM
it should still fix some issue Here is the scenario, I have this regex pattern: , You are missing a pair of parentheses:
Java Regex Missing a Match

Java Regex Missing a Match


By : user6052423
Date : October 05 2020, 07:00 AM
I wish did fix the issue. When you call vowelMatcher.find() inside your if condition, you tell the matcher to find the first string matching the specified pattern. In this case, it is "e". When you call it again in your while condition, the matcher finds the next match, in this case it is "o".
From there, it loops through the rest of the String. If you gave it the input "Hello World eeee", it would return "ooeeee", since you always discard the first match by calling .find() without calling .group() immediately after.
code :
int i = 0;
while (vowelMatcher.find()) {
    sb.append(vowelMatcher.group());
    i++;
}

return i == 0 ? "No matches" : sb.toString();  // return "no matches" if i is 0, otherwise, string
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