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Python Regular Expressions - Ignore sequence during searching


Python Regular Expressions - Ignore sequence during searching

By : user2949036
Date : November 15 2020, 06:54 AM
To fix this issue What you're asking for is a different regular expression.
The new regular expression would be the old one, with (\n?)? or the like after every non-quantifier character.
code :


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Searching and capturing a character using regular expressions Python

Searching and capturing a character using regular expressions Python


By : Daniel R J Walter
Date : March 29 2020, 07:55 AM
Any of those help Change result.groups() to result.group(1) and you will get just the single letter match.
A second problem with your code is that it will not find multiple results on one line. So instead of using re.search you'll need re.findall or re.finditer. findall will return strings or tuples of strings, whereas finditer returns match objects.
code :
import urllib
import re    

pat = re.compile('[a-z][A-Z]{3}([a-z])[A-Z]{3}[a-z]')
print ''.join(pat.findall(urllib.urlopen(
    "http://www.pythonchallenge.com/pc/def/equality.html").read())) 
Searching list of strings using regular expressions in python

Searching list of strings using regular expressions in python


By : Yusri Otai
Date : March 29 2020, 07:55 AM
help you fix your problem I have a list of Strings. I want to select the strings which match a certain pattern using regular expression. Python regular expressions dont take a list and I dont want to use loops. , Try:
code :
def searcher(s):
    if COMPILED_REGEXP_OBJECT.search(s):
        return s

matching_strings = filter(searcher, YOUR_LIST_OF_STRING)
matching_strings = filter(COMPILED_REGEXP_OBJECT.search, YOUR_LIST_OF_STRING)
How to ignore \n in regular expressions in python?

How to ignore \n in regular expressions in python?


By : Adam Swank
Date : March 29 2020, 07:55 AM
may help you . From the documentation:
Why does searching for > 100 different regular expressions slow my python script to a crawl?

Why does searching for > 100 different regular expressions slow my python script to a crawl?


By : Ivan Rykov
Date : March 29 2020, 07:55 AM
it should still fix some issue You are using regexes wrong; you should compile them. There is a cache in re module for the lazy people who do not compile regexes; the size of the cache is 100 on Python 2.7, 512 on Python 3.4. The size of the cache is available at re._MAXCACHE. After these 100 entries are exhausted, all compiled patterns are expelled from the cache. If you see your program using more than re._MAXCACHE regexes, you should precompile them using re.compile.
code :
regexes = [ re.compile(i) for i in regexes ]
for line in data:
    for regex in regexes:
        ret = regex.search(line)
        if ret is not None:
            print("Regex found")
megaregex = re.compile('|'.join(regexes))
for line in data:
    ret = megaregex.search(line)
    if ret is not None:
        print("Regex found")
Finding overlapping sequence with regular expressions with Python

Finding overlapping sequence with regular expressions with Python


By : Worried_user
Date : March 29 2020, 07:55 AM
With these it helps Since there is no overlapping numbers, a single trailing
assertion should be all you need.
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