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Is it possible to "appendListItem" starting from a specific number?


Is it possible to "appendListItem" starting from a specific number?

By : Jerry Zhou
Date : November 15 2020, 06:54 AM
will help you This is not possible with GAS.
The closest you can get is to continue the numbering of a list even if the list items are not consecutive in the document. To do that, get the list id of the previous list item using .getListId() on an existing item and then .setListId(id) on the new item you are appending.
code :


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"Enter another number (Y/N?)" process starting over instead of continuing when "Y"

"Enter another number (Y/N?)" process starting over instead of continuing when "Y"


By : kollan das
Date : March 29 2020, 07:55 AM
I hope this helps . I have two programs: , So I did a really quick test
code :
public static void main(String[] args) {

    Scanner game = new Scanner(System.in);

    while (true) {

        System.out.println("Enter another contestant (Y/N)?");
        String str = game.next();
        if (!str.equalsIgnoreCase("Y")) {
            break;
        }
    }

    System.out.println("I'm free");

}
Scanner game = new Scanner(System.in);

double num = 0;
double sum = 0;
int cnt = 0;

while (true) {
    System.out.println("Enter as many non-negative integers as you like ");
    System.out.println("one at a time and I will find the average");
    System.out.println("Enter done to stop entering numbers");

    double lowscore = Double.MAX_VALUE;
    double highscore = 0;

    System.out.print("enter number: ");
    String ans = game.next();
    while (!ans.equals("done")) {

        num = Double.parseDouble(ans);

        lowscore = Math.min(lowscore, num);
        highscore = Math.max(highscore, num);

        sum += num;
        cnt++;

        System.out.print("enter number: ");
        if (num > highscore) {
            highscore = num;
        }
        if (num < lowscore) {
            lowscore = num;
        }
        ans = game.next();
    }

    sum -= lowscore;
    sum -= highscore;

    System.out.println("Throwing out low score " + lowscore + " and high score " + highscore);
    System.out.println("Total Score " + sum + " count scores " + cnt + " avg score " + sum / cnt);

    System.out.println("Enter another contestant (Y/N)?");
    String str = game.next();
    if (!str.equalsIgnoreCase("Y")) {
        break;
    }
}
Enter as many non-negative integers as you like 
one at a time and I will find the average
Enter done to stop entering numbers
enter number: 1
enter number: 2
enter number: 3
enter number: 4
enter number: 5
enter number: 6
enter number: 7
enter number: 8
enter number: 9
enter number: 10
enter number: done
Throwing out low score 1.0 and high score 10.0
Total Score 44.0 count scores 10 avg score 4.4
Enter another contestant (Y/N)?
y
Enter as many non-negative integers as you like 
one at a time and I will find the average
Enter done to stop entering numbers
enter number: 1
enter number: 12
enter number: 13
enter number: 14
enter number: 15
enter number: 16
enter number: 17
enter number: 18
enter number: 19
enter number: 20
enter number: done
Throwing out low score 1.0 and high score 20.0
Total Score 168.0 count scores 20 avg score 8.4
Enter another contestant (Y/N)?
n
Why isn't my code returning the "maximum" number of consecutive 1's for the specific input "524275"?

Why isn't my code returning the "maximum" number of consecutive 1's for the specific input "524275"?


By : Mazamo
Date : March 29 2020, 07:55 AM
will help you After processing the first 15 ones in with the for loop, hold will actually have the value 15. Then you meet the first zero, and if(binary.charAt(i)=='0') { hold=count; count=1; } will reset count to 1. But then you immediately find another zero, and the same code if(binary.charAt(i)=='0') { hold=count; count=1; } stores 1 in hold and you loose the information 15.
An easy solution is just to remove the line hold=count; in this line. You already set hold three lines above. (And correctly, because you only do it if count is bigger then the previous best value.
code :
int current_consecutive_ones = 0;
int best_consecutive_ones = 0;
for(int i = 0; i < binary.length(); i++)
{
    if (binary.charAt(i) == '1')
        current_consecutive_ones++;
    else
        current_consecutive_ones = 0;

    if (current_consecutive_ones > best_consecutive_ones)
        best_consecutive_ones = current_consecutive_ones;
}
System.out.println(best_consecutive_ones);
Matching a part of sentence starting with "the" or "a" and ending with a number

Matching a part of sentence starting with "the" or "a" and ending with a number


By : Aya Waleed
Date : March 29 2020, 07:55 AM
Any of those help I need a regular expression that identifies the following: "[the or a] [text] [number]" , I think this will work... There maybe a less verbose way though
code :
\bthe\b(?:(?!\bthe\b).)*?\d+|\ba\b(?:(?!\ba\b).)*?\d+
var pattern = @"\bthe\b(?:(?!\bthe\b).)*?\d+|\ba\b(?:(?!\ba\b).)*?\d+";
var input = "The foo or the bar 100. A large machine 200. The transformer 100 and a bridge 200. GufftheGuff guffAguff is not matching 100";

Regex regex = new Regex(pattern, RegexOptions.IgnoreCase);

var matches = regex.Matches(input);

foreach (Match match in matches)
{
   Console.WriteLine(match.Value);
}
"the bar 100"
"A large machine 200"
"The transformer 100"
"a bridge 200"
PDO PHP string input starting with number ("2abcd") gets trimmed to only number ("2") in $stmt->b

PDO PHP string input starting with number ("2abcd") gets trimmed to only number ("2") in $stmt->b


By : Preeti Sharma
Date : March 29 2020, 07:55 AM
this one helps. You just need to check if the provided value is the same as the value after you cast it to an integer. If it is not, then throw an exception.
code :
public static function getImagePath($id) {
    $sql_fetch_opp = "select img from my_user where id=:id";
        $db = DAO::connect();
    try {
        if((string)$id !== (string)(int)$id)
        {
            throw new PDOException("Invalid id provided");
        }
        $stmt = $db->prepare($sql_fetch_opp);
        $stmt->bindParam(':id', $id);
        $stmt->execute();
        $imgPath = $stmt->fetch(PDO::FETCH_COLUMN);
        return $imgPath;
    } catch (PDOException $e) {
        Err::log($e);
        throw new MyException(Err::PDO_EXCPTION);
    }
}
QEMU AARCH64 "virt" Machine SMP CPUs Starting in "running" vs. "halted" State

QEMU AARCH64 "virt" Machine SMP CPUs Starting in "running" vs. "halted" State


By : user3295532
Date : March 29 2020, 07:55 AM
With these it helps This depends on the board model -- generally we follow what the hardware does, and some boards start all CPUs from power-on, and some don't. For the 'virt' board (which is specific to QEMU) what we generally do is use PSCI, which is the Arm standard firmware interface for powering SMP CPUs up and down (among other things; you can also use it for 'power down entire machine', for instance). On startup only the primary CPU is running, and it's the job of guest code to use the PSCI API to start the secondaries. That's what that psci node in the DTS is telling the guest -- it tells the guest what specific form of the PSCI ABI QEMU implements, and in particular whether the guest should use the 'hvc' or 'smc' instruction to call PSCI functions. What QEMU is doing here is emulating a "hardware + firmware" combination -- the guest executes an 'smc' instruction and QEMU performs the actions that on real hardware would be performed by a bit of firmware code running at EL3.
The virt board does also have another mode of operation which is intended for when you want to run a guest which is itself EL3 firmware (for instance if you want to run OVMF/UEFI at EL3). If you start QEMU with -machine secure=true to enable EL3 emulation and you also provide a guest firmware blob via either -bios or -drive if=pflash,..., then QEMU will assume your firmware wants to run at EL3 and provide PSCI services itself, so it will start with all CPUs powered on and let the firmware deal with sorting them out.
code :
    .equ PSCI_0_2_FN64_CPU_ON, 0xc4000003
    ldr x0, =PSCI_0_2_FN64_CPU_ON
    ldr x1, =4         /* target CPU's MPIDR affinity */
    ldr x2, =0x10000   /* entry point */
    ldr x3, =0         /* context ID: put into target CPU's x0 */
    smc 0
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