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How can I exclude a string if it ends in ".d.ts"?


How can I exclude a string if it ends in ".d.ts"?

By : Sadia Z. Shaikh
Date : November 15 2020, 06:54 AM
should help you out I am using regex type glob to include files in gulp. How can I use a regex to ignore strings that end with a ".d.ts" but include all others?
code :
.*(?<!\.d\.ts)$


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How do I replace a string that starts with "[id", has an unknown middle part and ends in "]"?

How do I replace a string that starts with "[id", has an unknown middle part and ends in "]"?


By : user2337874
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further The following will remove all occurences of [idsomething]. something will match all characters except for ].
code :
$newText = preg_replace('#\[id[^\]]+\]#', '', $subject);
$newText = preg_replace('#\[id\d+\]#', '', $subject);
Find string that begins with "X" and ends with "Y" and replaces content between

Find string that begins with "X" and ends with "Y" and replaces content between


By : sekharnaik
Date : March 29 2020, 07:55 AM
Hope this helps As Adam suggested, I was able to get this done using SimpleDOM (link: simplehtmldom.sourceforge.net).
code :
require_once('simple_html_dom.php');
$html = "This is some test code <img width='50' src='img/paddock1.jpg' /> And this is some additional text and an image: <img src='img/paddock2.jpg' />";

//uses function from simple_html_dom.php to make html parsable
$doc = str_get_html($html);

//finds each image in html and converts
foreach ($doc->find('img[src]') as $img) 
{

    //get src of image and assign to $src
    $src = $img->src;

    $imageBase = convertImage($src);

    $img->src = $imageBase;


}

$html = (string) $doc;

echo $html;

function convertImage($file)
{

    //finds file based on $src name from above and runs code if file exists
    if($fp = fopen($file,"rb", 0))
    {
       $picture = fread($fp,filesize($file));
       fclose($fp);
       //converts image file to base64
        $base64 = base64_encode($picture);

       //returns nessary data: + base64 code to $imageBase above to be inserted into html>img>src
       return 'data:image/png;base64,' . $base64;
    }
}
Extract a substring that starts with "http" and ends with ".mp3" from a string

Extract a substring that starts with "http" and ends with ".mp3" from a string


By : Theoren Smith
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You can use regular expressions for what you describe:
code :
In [48]: s='Link: http://google.com/song.mp3 Another link, http://yahoo.com/another_song.mp3'

In [49]: re.findall('http.*?mp3', s)
Out[49]: ['http://google.com/song.mp3', 'http://yahoo.com/another_song.mp3']
extract a specific string which start with "(/ " and ends with "/)" in java script from a long strin

extract a specific string which start with "(/ " and ends with "/)" in java script from a long strin


By : Rusbi Bie
Date : March 29 2020, 07:55 AM
will be helpful for those in need Extract a specific string which starts with "(/ " and ends with "/)" using javascript from a long string. I tried regular expression no luck , You can use the following code
code :
let result =  "Dear Mr./Ms. (/Name/),​Following up for the position of (/Developer/), I’d like to inquire about the progress of your hiring decision and the status of my job application. I am very eager to (/Work/) with your company.​Thanks for your time and consideration, and I look forward to hear back from you soon.​Sincerely,(/YourName/)";

let ans = result.match(/\/\w+\//g);

ans = ans.map(e => e.replace(/\//g, ''));
console.log(ans);
Ubuntu base64 encoded string ends with "o=" instead of apparently correct "=="

Ubuntu base64 encoded string ends with "o=" instead of apparently correct "=="


By : hardhead_q
Date : March 29 2020, 07:55 AM
should help you out In the instructions on this OAuth protocol, you can see that the example base64 encoding of "12345:verySecret" is , echo inducing newline character, try with -n flag with echo
code :
echo -n 12345:secret | base64
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