Extract pattern using regex

Extract pattern using regex

By : jojoma42
Date : November 15 2020, 06:54 AM
I wish this help you .* is greedy by default. Change .* in your regex to .*?. You could try this regex also,
code :

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Regex: extract last occurence of pattern

Regex: extract last occurence of pattern

By : Fmak
Date : March 29 2020, 07:55 AM
wish help you to fix your issue This regex will not work if address contains comma or number in it. If the address is always the text from the end of the string, then try with this regex:
code :
\s*([a-zA-Z ]+?)\s*$
Regex pattern to extract substring

Regex pattern to extract substring

By : user2294297
Date : March 29 2020, 07:55 AM
Does that help mystring = "q1)whatq2)whenq3)where" , You could try the below code which uses re.findall function,
code :
>>> import re
>>> s = "q1)whatq2)whenq3)where"
>>> m = re.findall(r'q\d+\)(?:(?!q\d+).)*', s)
>>> m
['q1)what', 'q2)when', 'q3)where']
Regex pattern to extract a String

Regex pattern to extract a String

By : user3084013
Date : March 29 2020, 07:55 AM
I hope this helps . I've tried to extract the following string C:\Windows\Microsoft.NET\Framework\v4.0.30319\Microsoft.Common.targets from the below text. , Change the non-capturing group at the last to positive lookahead.
code :
Regex pattern to extract row

Regex pattern to extract row

By : rohan
Date : March 29 2020, 07:55 AM
To fix this issue I have text file like the following:
code :
        pattern = "^(40211)"

        If match.Success Then
            sheet.Cells(i, 1).Value = line
            i += 1
        End If
Extract named group regex pattern from a compiled regex in Python

Extract named group regex pattern from a compiled regex in Python

By : Deepak Kumar
Date : March 29 2020, 07:55 AM
this one helps. There really doesn't appear to be a nicer way to do this, but here's a another approach, along the lines of this other answer but somewhat simpler. It will work provided that a) your patterns will always formed as a series of named groups separated by pipes, and b) the named group patterns never contain named groups themselves.
The following would be my approach if you're interested in all matches of each pattern. The argument to re.split looks for a literal pipe followed by the (?=<, the beginning of a named group. It compiles each subpattern and uses the groupindex attribute to extract the name.
code :
def nameToMatches(pattern, string):
    result = dict()
    for subpattern in re.split('\|(?=\(\?P<)', pattern):
        rx = re.compile(subpattern)
        name = list(rx.groupindex)[0]
        result[name] = rx.findall(string)
    return result
def nameToMatch(pattern, string):
    result = dict()
    for subpattern in re.split('\|(?=\(\?P<)', pattern):
        match = re.search(subpattern, string)
        if match:
    return result
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