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Array Size Declaration issue


Array Size Declaration issue

By : rsxjan
Date : November 14 2020, 04:51 PM
wish of those help The number of elements of the array, the array bound, must be a constant expression.
You have to use
code :
const int n = 5;
constexpr int n = 5;


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CUDA shared memory issue in outputs depending on extern declaration and size of array

CUDA shared memory issue in outputs depending on extern declaration and size of array


By : Fabrizio Pinna
Date : March 29 2020, 07:55 AM
I wish this helpful for you If you use the extern qualifier you need to pass the size of the shared memory when launching the kernel.
kernel<<< blocks, threads, size>>>(...)
'std::bad_alloc' in array declaration in root(CERN), depending on array size

'std::bad_alloc' in array declaration in root(CERN), depending on array size


By : Poulose
Date : March 29 2020, 07:55 AM
Hope that helps The originally posted code is not valid C++; it just happened to run when interpreted by CERN Root. To dynamically declare a 3D array:
code :
float*** doseArrayTotal = new float**[2350];
for(int i = 0; i < 2350; ++i){
  doseArrayTotal[i] = new float*[2350];
  for(int j = 0; j < 2350; ++j){
    doseArrayTotal[i][j] = new float[2350];
  }
}
vector<vector<vector<float> > > doseArrayTotal;
doseArrayTotal.resize(2350);
for (int i = 0; i < 2350; ++i) {
  doseArrayTotal[i].resize(2350);
  for (int j = 0; j < 2350; ++j){
    doseArrayTotal[i][j].resize(2350);
  }
}
float ValueEntered = 7.3;
float ValueExtracted;
doseArrayTotal[1][2][3] = ValueEntered;
ValueExtracted = doseArrayTotal[1][2][3];
How to initialize const size array in constructor without explicitly stating the size in class declaration?

How to initialize const size array in constructor without explicitly stating the size in class declaration?


By : Jimmy Gabriel
Date : March 29 2020, 07:55 AM
wish of those help You cannot do that: The size of the array is part of the type of the array, and hence of the class. The constructor is also part of the class. The class needs to exist first before you can call constructors, so the constructor call cannot influence the class definition.
Clang: How to get the macro name used for size of a constant size array declaration

Clang: How to get the macro name used for size of a constant size array declaration


By : Brendan Ronan
Date : March 29 2020, 07:55 AM
will help you As you noticed correctly, the source code is already preprocessed and it has all the macros expanded. Thus, the AST will simply have an integer expression as the size of array.
A little bit of information on source locations
code :
// clang::DeclRefExpr
//
//  ┌─ begin location
foo(VeryLongButDescriptiveVariableName);
//  └─ end location
// clang::BinaryOperator
//
//           ┌─ begin location
int Result = LHS + RHS;
//                 └─ end location
#define STR_MAX 2049
#define BAR(X) X

int main() {
  char inStrDef[STR_MAX];
  char inStrFunc[BAR(2049)];
  char inStrFuncNested[BAR(BAR(STR_MAX))];
}
// clang::VarDecl *VD;
// clang::ASTContext *Context;
auto &SM = Context->getSourceManager();
auto &LO = Context->getLangOpts();
auto DeclarationType = VD->getTypeSourceInfo()->getTypeLoc();

if (auto ArrayType = DeclarationType.getAs<ConstantArrayTypeLoc>()) {
  auto *Size = ArrayType.getSizeExpr();

  auto CharRange = Lexer::getAsCharRange(Size->getSourceRange(), SM, LO);
  // Lexer gets text for [start, end) and we want him to grab the end as well
  CharRange.setEnd(CharRange.getEnd().getLocWithOffset(1));

  auto StringRep = Lexer::getSourceText(CharRange, SM, LO);
  llvm::errs() << StringRep << "\n";
}
STR_MAX
BAR(2049)
BAR(BAR(STR_MAX))
Passing array by reference without explicitly stating the size of the array in function declaration

Passing array by reference without explicitly stating the size of the array in function declaration


By : Prudhvi Gsv
Date : March 29 2020, 07:55 AM
wish helps you You can't do that because std::arrays of different sizes are distinct types.
Either make it a function template as per aparpara's answer, or make it a function template that accepts a range as a pair of iterators. The latter option would make it independent of the container type and the element type. This is also consistent with the way the standard library does it:
code :
template <typename Iterator>
void Foo(Iterator first, Iterator last)
{ /* ... */ }
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