JQuery input form is not working

JQuery input form is not working

By : user2948643
Date : November 14 2020, 04:51 PM
With these it helps See the problem is that you are setting the same data, i.e. val in both cases. Check the following
code :
  <script type="text/javascript">
   $(document).ready(function($) {
    $('input#shortby').val(<?php echo (isset($_POST['shortby'])) ? json_encode($_POST['shortby']) : ''; ?>);
    $('input#radius').val(<?php echo (isset($_POST['radius'])) ? json_encode($_POST['radius']) : ''; ?>);
    $('ul li').on('click', function() {
        var shortbyVal, radiusVal;
        if($(this).data('val') === undefined){
            radiusVal = $(this).data('val2');
            shortbyVal = $('input#shortby').val();
        else if($(this).data('val2') === undefined){
            shortbyVal = $(this).data('val');
            radiusVal = $('input#radius').val();


 echo "POST VALUE: ". $_POST['shortby'];
 echo "POST VALUE: ". $_POST['radius'];

<form action="1.php" method="post" id="order">
  <input id="shortby" type="hidden" value="" name="shortby">
  <section class="container">
    <div class="dropdown">
       <div>Sort By: <?php echo $_POST['shortby']; ?>
          <li data-val="Featured"       ><a href="#" >Featured</a></li>
          <li data-val="Name"           ><a href="#" >Name</a></li>
          <li data-val="Price (Highest)"><a href="#" >Price (Highest)</a></li>
          <li data-val="Price (Lowest)" ><a href="#" >Price (Lowest)</a></li>


  <input id="radius" type="hidden" value="" name="radius">
  <section class="container">
    <div class="dropdown">
       <div>Radius: <?php echo $_POST['radius']; ?>
        <ul> <!-- Observe the change in data-val to data-val2 -->
          <li data-val2="10"> <a href="#" >10</a></li>
          <li data-val2="20"> <a href="#" >20</a></li>
          <li data-val2="30"> <a href="#" >30</a></li>
          <li data-val2="40"> <a href="#" >40</a></li>
          <li data-val2="50"> <a href="#" >50</a></li>

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Input Button not working on Jquery form

Input Button not working on Jquery form

By : user3779093
Date : March 29 2020, 07:55 AM
should help you out Your logic is flawed. You must not lower the flag (change to 0) if it's already raised (equal to 1). In addition, you should not directly call submit() again, just return true or false.
Fix with minimal changes to your original code:
code :
flag = 0; //lower by default
if (document.getElementById("user").value == "") {
    // slidedown some red css
    flag = 1;
} else {
    // dont show red css 

if (document.getElementById("email").value == "") {
    // slidedown some red css
    flag = 1;
} else {
    // dont show red css 
if (flag == 1) {
    // dont submit form
    return false;
else {
    return true;
jQuery form input into an array not working

jQuery form input into an array not working

By : Khaled Hassen
Date : March 29 2020, 07:55 AM
should help you out I'm working on a game and there is a form input where the user enters the number of characters. Once this happens more inputs appear for each character's name. My problem right now is reading those names into an array. , Try this way:
code :
$(".form").on('click', '#nameButton', function () {
    names = $(".newR").map(function () {
        return this.value;
jQuery Masked Input plugin not working on form input?

jQuery Masked Input plugin not working on form input?

By : jean
Date : March 29 2020, 07:55 AM
I wish this help you I have no experience of dataTables but from your code I think you are using the popup editor? If so you probably need to apply the mask in the event which is fired after the editor is opened like this:
code :
editor.on('onOpen', function () {
    $('#DTE_Field_phone').mask('(999) 999-9999');
Can't get jquery form input validation working

Can't get jquery form input validation working

By : Greg Sika
Date : March 29 2020, 07:55 AM
hop of those help? noob question... , You must load jquery in block
code :
<script src="//code.jquery.com/jquery-1.9.1.js" type="text/javascript">
<div class="imgform">
        <input type="text" id="imglogin" name="login">Password:
        <input type="password" id="imgpass" name="pass">
<a class="imglogin" href="#">Login</a>
            <div id="imgform"></div>
$(".imglogin").click(function () {
    var password = "111";
    if ($("#imgpass").val() != password) {
        $("#imgform").text("Incorrect password"); //I added div with id imgform
    } else {
        window.location.href = "http://google.com";
jquery-form-validator.js: Form input validates, but form itself fails validation. Only one input in form

jquery-form-validator.js: Form input validates, but form itself fails validation. Only one input in form

By : Navvi
Date : March 29 2020, 07:55 AM
To fix this issue I'm using jQuery-Form-Validator and most of it is going fine. , You probably should remove this part:
code :
onValidate : function($form) {
          return {
            element : $( this),
            message : 'This input has an invalid value for some reason'
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