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Multiple functions with the same name


Multiple functions with the same name

By : Artur
Date : November 14 2020, 04:51 PM
hope this fix your issue You are allowed to define two functions with the same name if they have different Types, or if they can be distinguished by their external parameter argument labels. The Type of a function is composed of the parameter Types in parentheses, followed by ->, followed by the return Type. Note that the argument labels are NOT a part of the function's Type. (But see UPDATE below.)
For example, the following functions both have the same name and are of Type (Int, Int) -> Int:
code :
// This:
func add(a: Int, b: Int) -> Int {
    return a + b
}

// Is the same Type as this:
func add(x: Int, y: Int) -> Int {
    return x + y
}
// Function A: This function has the Type (UITableView, Int) -> Int
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int { ... }

// Function B: This function has the Type (UITableView, NSIndexPath) -> UITableViewCell
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell { ... }

// Function C: This made up function will produce a compile-time error because
// it has the same name and Type as Function A, (UITableView, Int) -> Int:
func tableView(arg1: UITableView, arg2: Int) -> Int { ... }
func add(a: Int, to b: Int) -> Int {    // called with add(1, to: 3)
    println("This is in the first function defintion.")
    return a + b
}

func add(a: Int, and b: Int) -> Int {   // called with add(1, and: 3)
    println("This is in the second function definition")
    return a + b
}

let answer1 = add(1, to: 3)    // prints "This is in the first function definition"
let answer2 = add(1, and: 3)   // prints "This is in the second function definition"


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python 2.7.5, using functions to process user input, assigning new variables and multiple functions

python 2.7.5, using functions to process user input, assigning new variables and multiple functions


By : Anto David
Date : March 29 2020, 07:55 AM
should help you out Your getProd is a good start, but you have to return something for it to be useful.
code :
def getProd(n1,n2,n3):
    itotal = n1 * n2 * n3 
    return itotal
def displayProductData(first, second, third, total):
    print("The first value is = ", first);
    print("The second value is = ", second);
    print("The third value is = ", third)
    print("The Total is = ", total);
def main():
    isum1 = 0
    isum2 = 0
    isum3 = 0 

    isum1 = getValue()
    isum2 = getValue()
    isum3 = getValue() 
    itotal = getProd(isum1, isum2, isum3)

    displayProductData(isum1, isum2, isum3, itotal)
def get_value():
    #code

def get_sum():
    #code

def get_prod()
def get_sum(first, second):
    return first + second

def get_prod(n1,n2,n3):
    return n1 * n2 * n3
def main():
    isum1 = getValue()
    isum2 = getValue()
    isum3 = getValue() 
    itotal = getProd(isum1, isum2, isum3)

    displayProductData(isum1, isum2, isum3, itotal)
def display_product_data(first, second, third, total):
    print "The first value is = ", first
    print "The second value is = ", second
    print "The third value is = ", third
    print "The Total is = ", total
('The first value is = ', 2.0)
('The second value is = ', 3.0)
('The third value is = ', 4.0)
('The Total is = ', 24.0)
The first value is =  2.0
The second value is =  3.0
The third value is =  4.0
The Total is =  24.0    
call multiple functions by order use ng-click, single click and pass the same variable to multiple functions angularjs

call multiple functions by order use ng-click, single click and pass the same variable to multiple functions angularjs


By : DrSoccerball_
Date : March 29 2020, 07:55 AM
hop of those help? ng-click cannot call googlesearch function and keywordsearch fuction. , Call the second function inside your first one,
code :
$scope.googlesearch=function(keyword){
    alert("do the googlesearch 1 "+keyword);
    $scope.keywordsearch(keyword);
  };
How do I structure Cloud Functions for Firebase to deploy multiple functions from multiple files?

How do I structure Cloud Functions for Firebase to deploy multiple functions from multiple files?


By : Cindy Bohorquez
Date : March 29 2020, 07:55 AM
may help you . Ah, Cloud Functions for Firebase load node modules normally, so this works
structure:
code :
/functions
|--index.js
|--foo.js
|--bar.js
|--package.json
const functions = require('firebase-functions');
const fooModule = require('./foo');
const barModule = require('./bar');

exports.foo = functions.database.ref('/foo').onWrite(fooModule.handler);
exports.bar = functions.database.ref('/bar').onWrite(barModule.handler);
exports.handler = (event) => {
    ...
};
exports.handler = (event) => {
    ...
};
Does Google Cloud Functions support multiple functions in a single deployment package?

Does Google Cloud Functions support multiple functions in a single deployment package?


By : Shubha
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I do not think it is possible to deploy multiple functions using one command for google cloud - as mentioned by various posts. To make things easy, I ended up using the following command:
code :
sed -n 's/exports\.\([a-zA-Z0-9\-_#]*\).*/\1/p' index.js | xargs -I {} gcloud beta functions deploy {} --trigger-http
How do I pass multiple functions (with arguments attached) through a function and output them as a list of functions WIT

How do I pass multiple functions (with arguments attached) through a function and output them as a list of functions WIT


By : user1496075
Date : March 29 2020, 07:55 AM
may help you . if i'm understanding correctly, you probably want to use functools.partial.
I changed the input a little to accept any number of (function, kwarg) arguments. If you are specifically passing in two parameters (fxn1, fxn2), you can use the kwargs assigment (where the type error was coming from). In order to pass in an arbitrary number of functions, you need to use *args and not **kwargs in function_collector.
code :
def function_collector(*func_kwarg_pairs):
    ready_to_call = []
    for func, kwargs in func_kwarg_pairs:
        new_function = partial(func, **kwargs)
        ready_to_call.append(new_function)
    return ready_to_call
    # as a one-line func: return [partial(func, *kwargs) for func, kwargs in func_kwarg_pairs]

# with your two funcs:
if __name__ == '__main__':
    pairs = [(fxn1, {"name" : "joe", "employment_status" : "coder"}), (fxn2, {"age" : 12, "job" : "farmer"})]
    to_be_called = function_collector(*pairs)
    for item in to_be_called:
        item()
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