Remove trailing numbers from string js regexp

Remove trailing numbers from string js regexp

By : user2948587
Date : November 14 2020, 04:51 PM
help you fix your problem I am trying to remove the trailing numbers from the string using JavaScript RegExp. Here is the example. , You could use this regex to match all the trailing numbers.
code :
string.replace(/\d+$/, "")

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Oracle regexp - removing trailing underscore and numbers from string

Oracle regexp - removing trailing underscore and numbers from string

By : user3504653
Date : March 29 2020, 07:55 AM
Hope that helps You need to use REGEXP_REPLACE with the regex expression '\_[[:digit:]]{1,}'
This translates to find the (escaped) underscore with one or more digits after it:
code :
SELECT REGEXP_REPLACE('a_b', '\_[[:digit:]]{1,}'),
       REGEXP_REPLACE('aaa_1', '\_[[:digit:]]{1,}'),
       REGEXP_REPLACE('c_21', '\_[[:digit:]]{1,}'),
       REGEXP_REPLACE('bb_5', '\_[[:digit:]]{1,}')
  FROM dual;
SELECT REGEXP_REPLACE('bb_5b', '\_[[:digit:]]{1,}$'),
       REGEXP_REPLACE('bb_5b', '\_[[:digit:]]{1,}'),
       REGEXP_REPLACE('bb_55', '\_[[:digit:]]{1,}$'),
       REGEXP_REPLACE('bb_55', '\_[[:digit:]]{1,}')
  FROM dual;
How to remove any trailing numbers from a string?

How to remove any trailing numbers from a string?

By : Ringzero Gamespr
Date : March 29 2020, 07:55 AM
hop of those help? This solution should be a bit more efficient because it first checks to see if the string contains a number, then it checks to see if the string ends in a number.
code :
 CREATE FUNCTION dbo.trim_ending_numbers(@columnvalue AS VARCHAR(100)) RETURNS VARCHAR(100)
    --This will make the query more efficient by first checking to see if it contains any numbers at all
    IF @columnvalue NOT LIKE '%[0-9]%'
        RETURN @columnvalue

    DECLARE @counter INT
    SET @counter = LEN(@columnvalue)

    IF ISNUMERIC(SUBSTRING(@columnvalue,@counter,1)) = 0
        RETURN @columnvalue 

    WHILE ISNUMERIC(SUBSTRING(@columnvalue,@counter,1)) = 1 OR SUBSTRING(@columnvalue,@counter,1) = ' '
        SET @counter = @counter -1
        IF @counter < 0
    SET @columnvalue = SUBSTRING(@columnvalue,0,@counter+1)

    RETURN @columnvalue
SELECT dbo.trim_ending_numbers('More blah 12321 123123 123132')
'More blah'
RegExp: How to remove leading and trailing groups if present from a string

RegExp: How to remove leading and trailing groups if present from a string

By : Alexis d'Oultremont
Date : March 29 2020, 07:55 AM
Does that help You just have to make the middle part lazy, by adding a ? after the +:
code :
Rewrite URL condition - Change particular string & remove trailing numbers

Rewrite URL condition - Change particular string & remove trailing numbers

By : 彭永顺
Date : March 29 2020, 07:55 AM
will help you What's the best way to rewrite URLs as 301 redirects with the following conditions? , You can have this rule just below RewriteEngine On line:
code :
RewriteEngine On

RewriteRule ^c/([\w-]+/.+)-[\d_]+/?$ /category/$1 [L,NC,R=301]
Remove trailing numbers from String

Remove trailing numbers from String

By : Naveen Jp
Date : March 29 2020, 07:55 AM
seems to work fine You can use NumberFormater and set minimum and maximum fraction digits:
code :
let double1 = 1.12
let double2 = 0.00007067999999

let numberFormatter = NumberFormatter()
numberFormatter.minimumFractionDigits = 2
numberFormatter.maximumFractionDigits = 8
numberFormatter.minimumIntegerDigits = 1
numberFormatter.string(for: double1) ?? ""   // "1.12"
numberFormatter.string(for: double2) ?? ""   // "0.00007068"
numberFormatter.roundingMode = .down
numberFormatter.string(for: double2) ?? ""   // "0.00007067"
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