Any of those help I have list of lists that are all the same structure and I want to alter one element of each of the lists in the second tier. In other words, I have a single list with objects x, y & z. This list is repeated multiple times in another list. I need to change x in each of these lists. What is the best way to do this? , Simply return the modified obj instead of re-creating a list.
fixed the issue. Will look into that further I found a new solution that is even simpler than R. Schifini's elegant solution, so now I answer my own question :) The apply family also provides a recursive version called rapply, and it works perfectly on nested lists, see these examples.
How to create a sequentially ordered list in R with lapply and replicate?
By : Martin
Date : March 29 2020, 07:55 AM
it helps some times I have been trying to avoid for loops in R. However, I have had issues with using lapply with replicate in that the lists I obtain have ordering that are not sequential. For example, the following code: , You can just call unlist() on the result, e.g.:
may help you . You should note that lapply() itself is just a wrapper for a well constructed for() loop, so you're not gaining any efficiency, just perhaps readability. That aside, the easiest approach is to add names to the lists going into your nested lapply() calls: