Populate drop down list from SQL Server database

Populate drop down list from SQL Server database

By : bashii
Date : November 14 2020, 04:51 PM
wish helps you I have an ASPX page that has a drop down on it. , Well, I think you forget to bind your dropdownlist like;
code :
using(SqlConnection con = new SqlConnection(connString))
using(SqlCommand cmd = con.CreateCommand())
    using(SqlDataReader ddlValues = cmd.ExecuteReader())

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need to get value from the database and populate a drop down list using jQuery

need to get value from the database and populate a drop down list using jQuery

By : Evan Hammond
Date : March 29 2020, 07:55 AM
like below fixes the issue I need to populate a dropdown list when I select a certain value and the options need to be queried from the database. , You can do it with jQuery and AJAX
code :
jQuery.post('dropdownValues.php', {parameterSentToServer1:'value', param2:'value2'}, function(data){jQuery('#mydropdown option').remove(); //Remove current options
for (var option in data.results){
    jQuery('#mydropdown').append('<option value="'+option.value+'">'+option.name+'</option>');
}}, 'json');
echo '{results:[{value:1, name:'Option1'}, {value:2, name:'Option2'}]};
how to populate a drop down list from the database with jstl?

how to populate a drop down list from the database with jstl?

By : user2144030
Date : March 29 2020, 07:55 AM
help you fix your problem I have not tested your code, but please add a breakpoint in the server side to check how many elements you have in the list. Maybe it is also empty in the server side.
The second point is that this code
code :
<option value="${aff}"></option>
<option value="${aff}">${aff}</option>
Populate drop down list from database

Populate drop down list from database

By : user2268002
Date : March 29 2020, 07:55 AM
Hope this helps I always use a function, since select boxes are something I end up creating a lot...
code :
function select($name, $default, $values, $style='', $param='') {
        $html = '<select name="'.$name.'" style="'.$style.'" '.$param.' >';
        foreach($values as $i => $data) {
            if (isset($data['noFormat'])) { 
                $html .= '<option value="'.$data['value'].'" '.(($data['value']==$default)?'SELECTED="SELECTED"':'').' '.
                         (isset($data['style']) ? ' style="'.$data['style'].'" ' : '').'>'.$data['text'].'</option>';
            } else {
                $html .= '<option value="'.htmlentities($data['value']).'" '.(($data['value']==$default)?'SELECTED="SELECTED"':'').' '.
                         (isset($data['style']) ? ' style="'.$data['style'].'" ' : '').'>'.htmlentities($data['text']).'</option>';
        $html .= '</select>';
        return $html;                 
$default[] = array('value' => '0',   'text' => 'Select a City...');
while($row = mysql_fetch_assoc($result)) {  
    $list[] = array('value' => $row['city_id'], 'text' => $row['city_name']);
$list = array_merge($default,$list);
how to populate a drop down list from the database using iterator? jsp

how to populate a drop down list from the database using iterator? jsp

By : Chris
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I'm trying to populate a drop down with types of cars from my database, I already secceed on doing this to a list on another jsp page, but now when I want to do the same to a drop down list, its not working. I can see that its moving over the table on the database because on my drop down list I'm getting 3 blank spaces. (my table contain 3 vehicles at the moment). , replace
code :
 <option value= <%=vehicles.getId()%> ${vehicles.getMake()} </option>
<option value= <%=vehicles.getId()%>><%={vehicles.getMake()%> </option>
how to populate a drop down list from my SQL database using php

how to populate a drop down list from my SQL database using php

Date : March 29 2020, 07:55 AM
I wish this helpful for you It's because you're using old function mysql_fetch_array it should be mysqli_fetch_array.
Also mysql_error should be mysqli_error which accepts connection as single parameter.
code :
$sql = "SELECT category_name FROM category ORDER BY RAND() LIMIT 1";
$result=mysqli_query($conn, $sql) or die ("Query to get data from category failed: ".mysqli_error(conn));
    while ($row = mysqli_fetch_array($result)) {
    echo "<option>" . $category_name . "</option>";
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