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what is the syntax error in the line


what is the syntax error in the line

By : user2948468
Date : November 14 2020, 04:51 PM
like below fixes the issue Your code works perfectly fine, but maybe the demo below helps you to get rid of the issue. I also tested it with a way older angular version.
code :
angular.module('testApp', [])

.controller('testCtrl', function($scope) {
  var people = [{
      FirstName: 'John',
      LastName: 'Rambo'
    }, {
      FirstName: 'John',
      LastName: 'Rambo 2'
    }, {
      FirstName: 'Silvester',
      LastName: 'Stallone'
    }, {
      FirstName: 'Chuck',
      LastName: 'Norris'
    }
  ];

  $scope.vm = {
    SearchText: 'John',
    GetRequests: function() {
      return people;
    }

  };
});
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-app="testApp" ng-controller="testCtrl">
  <div ng-repeat="r in vm.GetRequests() | filter: vm.SearchText | orderBy:['LastName','FirstName']">
    {{r.FirstName}} {{r.LastName}}
  </div>
</div>


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Error: You have an error in your SQL syntax; check the manual that corresponds .. syntax to use near '1' at line 1

Error: You have an error in your SQL syntax; check the manual that corresponds .. syntax to use near '1' at line 1


By : mcfetridgewilliam
Date : March 29 2020, 07:55 AM
Hope that helps You have added additional 1 at the end of query. It should be like this:
code :
$sql = "UPDATE `posts` SET `Tilte` = '$Title',`Author` = '$Author',`Date` =   '$Date',`Content` = '$Content' WHERE `posts`.`ID` = '$ID'";
SQL syntax error MariaDB server version for the right syntax to use near 'WHERE ID = 4' at line 1

SQL syntax error MariaDB server version for the right syntax to use near 'WHERE ID = 4' at line 1


By : Purpwood
Date : March 29 2020, 07:55 AM
To fix the issue you can do You have empty $entry_database variable. As you see in error: ListEmail, Title FROM WHERE ID bewteen FROM and WHERE should be name of table. Proper syntax of SELECT:
code :
SELECT columns FROM table [optional things as WHERE/ORDER/GROUP/JOIN etc]
SELECT ID, ListStID, ListEmail, Title FROM some_table_you_got WHERE ID = '4'
Parse error: syntax error, unexpected '<<'(T_SL) on line 2 using php heredoc syntax

Parse error: syntax error, unexpected '<<'(T_SL) on line 2 using php heredoc syntax


By : user3213405
Date : March 29 2020, 07:55 AM
this will help Heredoc syntax requires a newline character immediately after the identifier, before the string content:
code :
$name = <<<SQL
my name is amit
SQL;
echo $name;
SQL syntax error MariaDB server version for the right syntax to use near '@hotmail.com,Employee)' at line 1

SQL syntax error MariaDB server version for the right syntax to use near '@hotmail.com,Employee)' at line 1


By : prashanth
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I am trying to make a sign up page using php and then when I write the mysql statements below it won't accept it rather it will spit out an error which I am trying to figure out for hours now. , Make sure you use proper quotes if you insert strings:
code :
$query = "INSERT INTO users(username, password,name,surname,email,role)VALUES('$username', '$password','$name','$lastname','$email','$role')";
error in your SQL syntax; MariaDB server version for the right syntax to use near ''studentid') VALUES ('52')' at line 1

error in your SQL syntax; MariaDB server version for the right syntax to use near ''studentid') VALUES ('52')' at line 1


By : Lars Hammarberg
Date : March 29 2020, 07:55 AM
like below fixes the issue You should use variables inside brackets and don't quote columns... And maybe, you should avoid quotation of table names, only values need to be quoted:
code :
$newAdmissionQ = "INSERT INTO admission (studentid) VALUES ('{$latestStudentID}')";
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