access to attribute through attrs.val or attrs.$set(attname, val)

access to attribute through attrs.val or attrs.$set(attname, val)

By : Maciek
Date : November 14 2020, 04:51 PM
this will help There is a single difference between both the syntax that, writing attrs.$set( 'skip-watch-value', true ); will also modify the DOM element (see by inspecting element) and sets the value while attrs.skipWatchValue = true; will not modify the DOM element.
code :

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Get the name of a custom attribute from attrs.xml

Get the name of a custom attribute from attrs.xml

By : jrltr
Date : March 29 2020, 07:55 AM
Any of those help Well I don't know why I didn't find it but the function I was looking for is getResourceEntryName which actually does exactly what I want
In my case if I want "jedi" I will do :
code :
String name = getResources().getResourceEntryName(R.attr.sw_jedi);
How to get the value of a custom attribute (attrs.xml)?

How to get the value of a custom attribute (attrs.xml)?

Date : March 29 2020, 07:55 AM
wish help you to fix your issue No, this is not the correct way, as the integer R.attr.customColorFontContent is a resource identifier generated by Android Studio when your app is compiled.
Instead, you'll need to get the color that is associated with the attribute from the theme. Use the following class to do this:
code :
public class ThemeUtils {
    private static final int[] TEMP_ARRAY = new int[1];

    public static int getThemeAttrColor(Context context, int attr) {
        TEMP_ARRAY[0] = attr;
        TypedArray a = context.obtainStyledAttributes(null, TEMP_ARRAY);
        try {
            return a.getColor(0, 0);
        } finally {
ThemeUtils.getThemeAttrColor(context, R.attr.customColorFontContent);
What is returned ? R inner join S using (ATTRS) where R and S have no common ATTRS

What is returned ? R inner join S using (ATTRS) where R and S have no common ATTRS

By : sangam upendra
Date : March 29 2020, 07:55 AM
help you fix your problem I know that R inner join S using (ATTRS) is effectively a natural join that instead of automatically equating all same-named attributes of R and S, only manually equates the given same-named attributes. , Yes Result will be be Cartesian product in SQL...
'NoneType' object has no attribute 'attrs'

'NoneType' object has no attribute 'attrs'

By : Frank
Date : March 29 2020, 07:55 AM
should help you out I can't see your full code but I think your problem is that you don't know how GUI frameworks works.
First: mainloop starts everything and it shows window. Everything before mainloop() is executed before you even see window.
code :
import requests
from bs4 import BeautifulSoup
import tkinter as tk

URL = "https://www.instagram.com/{}/"

def parse_data(s):
    data = {}
    s = s.split("-")[0]
    s = s.split()
    data['Followers'] = s[0]
    data['Following'] = s[2]
    data['posts'] = s[4]
    return data

def scrape_data(username):
    r = requests.get(URL.format(username))
    s = BeautifulSoup(r.text, "html.parser")
    meta = s.find("meta", property="og:description")
    return parse_data(meta.attrs['content'])

def on_click():
    username = entry.get()
    username = username.strip()
    if username:
        data = scrape_data(username)
        label['text'] = data
        label['text'] = "Need username"

if __name__ =="__main__": 

    root = tk.Tk()

    entry = tk.Entry(root)
    entry.grid(row=0, column=1)

    label = tk.Label(root)
    label.grid(row=1, column=1)

    button = tk.Button(root, text="Scrape", command=on_click)
    button.grid(row=2, column=1)

MongoDB query using .attrs attribute

MongoDB query using .attrs attribute

By : rediceism
Date : March 29 2020, 07:55 AM
will help you The period in the key is a problem. If we assume it is good, I guess you should construct your query like:
mongo.bson.buffer.append(buf, ".attrs.A1", "1")
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