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Efficient way to look up dictionary


Efficient way to look up dictionary

By : Tuấn Tưng Tửng
Date : November 14 2020, 04:48 PM
I wish this helpful for you It really depends on how large your document is, whether your keyword list is static, and whether you need to find multi-word phrases. The naive way to do it is to look up every word from the document in the dictionary. Because dictionary lookups are O(1), looking up every word will take O(n) time, where n is the number of words in the document. If you need to find multi-word phrases, you can post-process the output to find those.
That's not the most efficient way to do things, but it's really easy to implement, reasonably fast, and will work very well if your documents aren't huge.
code :


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Which is faster/more efficient: Dictionary<string,object> or Dictionary<enum,object>?

Which is faster/more efficient: Dictionary<string,object> or Dictionary<enum,object>?


By : Ehsen
Date : March 29 2020, 07:55 AM
wish of those help Certainly the enum version is better (when both are applicable and make sense, of course). Not just for performance (it can be better or worse, see Rashack's very good comment) as it's checked compile time and results in cleaner code.
You can circumvent the comparer issue by using Dictionary and casting enum keys to ints or specifying a custom comparer.
Efficient dictionary inversion on dictionary like file

Efficient dictionary inversion on dictionary like file


By : Rakesh Satapathy
Date : March 29 2020, 07:55 AM
To fix this issue Been having trouble efficiently inverting (swapping the values for keys and the keys for values) a large (2.8GB) dictionary stored in a file. Efficiency is the problem, my current solution is to: , I would suggest the following 3 pass solution:
Most efficient way to populate dictionary keys with dictionary

Most efficient way to populate dictionary keys with dictionary


By : kjp
Date : March 29 2020, 07:55 AM
wish help you to fix your issue If you have a static set of cities, then you could store in a map city name as a key and index of that city as a value. In addition, for each person you can store a list of visits, where i-th element of that list denotes the number of visits in i-th city:
code :
places = {"LA": 0, "San Jose": 1, "NY": 2}
friends = {"John": [0, 0, 0], "Carter": [0, 0, 0], "Bill": [0, 0, 0]}
friends["John"][places["NY"]] += 1
Most efficient way to find the key of the smallest value in a dictionary from a subset of the dictionary

Most efficient way to find the key of the smallest value in a dictionary from a subset of the dictionary


By : helga
Date : March 29 2020, 07:55 AM
should help you out You can use a dictionary view with set operations to select only keys from your input sequence:
code :
min(f.viewkeys() & o, key=f.get)
min(f.keys() & o, key=f.get)
set_o = set(o)
min(f, key=lambda k: f[k] if k in set_o else float('inf'))
>>> o = [1, 2, 4, 6]
>>> f = {1: 10, 2: 5, 3: 1, 4: 3, 5: 7, 6: 9}
>>> min(f.viewkeys() & o, key=f.get)
4
>>> set_o = set(o)
>>> min(f, key=lambda k: f[k] if k in set_o else float('inf'))
4
The most efficient way of Adding to a Dictionary within a Dictionary

The most efficient way of Adding to a Dictionary within a Dictionary


By : user3929795
Date : March 29 2020, 07:55 AM
it fixes the issue After completing a task in Java, I have now been required to produce the same results in C# and I am in need of some help. The object that I am using is: , I believe this would work:
code :
if (full_map.ContainsKey(int.Parse(pop_cy_st_intrst[0])))
    full_map[int.Parse(pop_cy_st_intrst[0])].Add(innerKeyStr, innerValueList);
else
    full_map.Add(int.Parse(pop_cy_st_intrst[0]), new Dictionary<string, List<int>>());
full_map.Add(int.Parse(pop_cy_st_intrst[0]), new Dictionary<string, List<int>>() { { innerKeyStr, innerValueList } });
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