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C++ - Which are variable by " Uint "?


C++ - Which are variable by " Uint "?

By : hana
Date : November 14 2020, 04:48 PM
wish of those help Which are variable by " Uint "? is that there are " Uint8 ", " Uint16 ", etc ... , uint is not a standard type. On some system uint is typedefed as
code :
typedef unsigned int uint ;


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AS3: declaring an "undefined" parameter for int, uint or Number

AS3: declaring an "undefined" parameter for int, uint or Number


By : Hareesh
Date : March 29 2020, 07:55 AM
To fix the issue you can do UPD (from my comment): It is certainly not a good practice to pick some magic number to indicate value absence, unless you can be completely sure this magic number would not appear as a result of some arithmetics (which generally is true). So the best approach here is either to use a wider type than int (e.g. Number), or pass some flag (Boolean value) to function, as well as int, to indicate actual value absence. Choice should depend on whether you want to emphasize the importance of fact that passed value is integral.
code :
function setMyValue (myVar : Number = NaN) : void
{
    if ( isNaN(myVar) )
    {
        /* Generate a value for myVar */
    }
    else
    {
        /* Use the supplied value for myVar */
    }
}
function setMyValue (isIntValueSupplied : Boolean = false, intValue : int = 0) : void
{
    if ( isIntValueSupplied )
    {
        /* Generate or use a default value of intValue */
    }
    else
    {
        /* Use the supplied value for intValue */
    }
}
What is the meaning of colon (:) operator in "uint isWidget : 1;" in Qt?

What is the meaning of colon (:) operator in "uint isWidget : 1;" in Qt?


By : André Duarte
Date : March 29 2020, 07:55 AM
I hope this helps you . This is part of C struct notation - you can specify the size of an integer field in bits by using a : numBits after the property name.
I must assume that the same syntax can be used in a C++ class (i'm a C guy, but i'm sure that this is doing the same thing in C++)
"invaiid operands to binary *" when assigning to uint* after g_malloc()

"invaiid operands to binary *" when assigning to uint* after g_malloc()


By : Nick Maxwell
Date : March 29 2020, 07:55 AM
I hope this helps . I have the following code segment
code :
 error: invalid operands to binary *
                            ^^^^^^
No visibility specified. Defaulting to "public". function transfer(address receiver, uint amount);

No visibility specified. Defaulting to "public". function transfer(address receiver, uint amount);


By : A.Brehm
Date : March 29 2020, 07:55 AM
should help you out There's nothing necessarily wrong with your code - the compiler is just warning you that you didn't specify a visibility scope, and that it'll be defaulting it to public.
Something like this is probably what you want:
code :
function transfer(address receiver, uint amount) external {}
How to convert "uint" type into "string" type in Golang?

How to convert "uint" type into "string" type in Golang?


By : Alok Srivastava
Date : March 29 2020, 07:55 AM
may help you . Use strconv.FormatUint():
code :
package main

import (
    "fmt"
    "strconv"
)

func main() {
    var n uint = 123
    var s string = strconv.FormatUint(uint64(n), 10)
    fmt.Printf("s=%s\n", s)
}
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