Scala - Creating a function to produce Unary string or integer values

Scala - Creating a function to produce Unary string or integer values

By : nathanaelphilip
Date : November 14 2020, 04:48 PM
Hope this helps Hello fellow Scala programmers, , I guess I'll have to go with this solution.
code :
package exprP

object ExprObj {

  abstract class UPair[T] {
    def getPositive():T
    def getNegative():T

  object UString extends UPair[String] {
    def getPositive():String = "+"
    def getNegative():String = "-"

  object UInt extends UPair[Int] {
    def getPositive():Int = 1
    def getNegative():Int = -1

  abstract class Unary
  case class Positive() extends Unary
  case class Negative() extends Unary

  def unaryFunc[T](u:Unary, p:UPair[T]):T = {
    u match {
      case Positive() => p.getPositive()
      case Negative() => p.getNegative()


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How to produce integer literal as an attribute in Scala XML output?

How to produce integer literal as an attribute in Scala XML output?

By : Iron Maiden
Date : March 29 2020, 07:55 AM
wish helps you Look like your XML is violating XML specification according to this each attribute value must begin with a double quote. See AttValue rule.
code :
val a : String = 10
implicit def intToString(i:Int) = i.toString  
val a : Int = 10
val b  = <Test attr={a}/>
How to convert a whole list of string to integer values in Scala

How to convert a whole list of string to integer values in Scala

By : user2741132
Date : March 29 2020, 07:55 AM
hop of those help? So, I have a list of strings like this. , map the List using toInt :
code :
List("12", "33", "77").map(_.toInt)
import scala.util.{Success, Try}
List("12", "33", "77", "bad").map(s => Try(s.toInt))
    .collect { case Success(x) => x }

res2: List[Int] = List(12, 33, 77)
List("12", "33", "77", "bad").filter(_.matches("[0-9]+")).map(_.toInt)
res7: List[Int] = List(12, 33, 77)
A function to produce unary representation

A function to produce unary representation

By : plqubeqb
Date : March 29 2020, 07:55 AM
seems to work fine (define int-unary (lambda (n) (if (= n 0) 'z (cons 's (int-unary(n-1))))))
This is the thing i got finally and it gave me the desired output.
How to produce a set of Char from a set of String in Scala

How to produce a set of Char from a set of String in Scala

By : amsr
Date : March 29 2020, 07:55 AM
wish helps you The IDE error isn't correct, but manually supplying type parameters to map is going to cause you problems, because the signature of map is really:
code :
final def map[B, That](f: (A) ⇒ B)(implicit bf: CanBuildFrom[List[A], B, That]): That
<console>:12: error: wrong number of type parameters for method map: [B, That](f: String => B)(implicit bf: scala.collection.generic.CanBuildFrom[scala.collection.immutable.Set[String],B,That])That
scala> val strings = Set("abc", "def", "ijk")

scala> strings.map(_.head)
res1: scala.collection.immutable.Set[Char] = Set(a, d, i)
scala> strings.map[Char, Set[Char]](_.head)
res6: Set[Char] = Set(a, d, i)
concatenate string and integer to produce byte array c++

concatenate string and integer to produce byte array c++

By : ThanosD
Date : March 29 2020, 07:55 AM
wish helps you There are lots of ways to do this, but here's one using a std::vector to hold the destination buffer (and manage all the memory allocation and deallocation associated with it) and std::memcpy (which is similar to System.arraycopy) to do the copying.
code :
  unsigned long  part1 = 0x0100000002;
  std::string part2 = "some_str";

  // create a vector big enough to hold both components
  std::vector<char> buffer(sizeof(part1) + part2.size());

  // copy the string into the beginning of the buffer
  std::memcpy(&buffer[0], &part2[0], part2.size());
  // copy the int into the space after the string
  std::memcpy(&buffer[part2.size()], &part1, sizeof(part1));

  std::cout.write(&buffer[0], buffer.size());
  std::cout << "\n";
  std::stringstream ss;
  ss.write(&part2[0], part2.size());
  ss.write(reinterpret_cast<const char*>(&part1), sizeof(part1));

  std::string buf = ss.str();

  std::cout.write(buf.c_str(), buf.size());
  std::cout << "\n";
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