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Getting ERROR unexpected token in Hibernate 4


Getting ERROR unexpected token in Hibernate 4

By : user2948172
Date : November 14 2020, 04:48 PM
help you fix your problem member is a reserved word in HQL. Escape it by adding a table alias.
Also, since member is of type Player, when your where clause contains member you need to provide a parameter of type Player. Alternatively if you want to provide the ID as you're doing, you need to explicitly search for the id:
code :
 foundMember = (ClanMember) getSession()
            .createQuery("from ClanMember c where c.member = :member")
            .setParameter("member", someInstanceOfPlayer);
            .uniqueResult();
 foundMember = (ClanMember) getSession()
            .createQuery("from ClanMember c where c.member = :member")
            .setParameter("member", idOfAPlayer);
            .uniqueResult();


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Syntax Error Hibernate - unexpected token: ON

Syntax Error Hibernate - unexpected token: ON


By : José Pedro Simão
Date : March 29 2020, 07:55 AM
like below fixes the issue You changed it to native SQL but you are making a projection with attributes from both VLC and camera objects, You need to either restrict the select to VLC objects so Hibernate knows how to map the requested attribute list into VLC objects, or explicitly convert them yourself by receiving a List of OBject[] then selecting each value yourself.
Error with Hibernate HQL - unexpected token:

Error with Hibernate HQL - unexpected token:


By : gdergan
Date : March 29 2020, 07:55 AM
Any of those help You cannot use named parameters for Hibernate queries. You can get around this by manually appending the name of the table into your hql string. Your code would look instead like this:
code :
String hql = "FROM " + className + " WHERE userCreate like ':userName'";
Query query = session.createQuery(hql);
query.setParameter("userName", userName);
List<Node> result = query.list();
Unexpected token error with JPA, Hibernate and QueryDSL

Unexpected token error with JPA, Hibernate and QueryDSL


By : Osama Ramadan
Date : March 29 2020, 07:55 AM
it helps some times I'm developing a Data Access Layer based on JPA by using Hibernate as ORM and QueryDSL in order to write type-safe queries.
code :
Organization.class.getName()
public long count() {
  JPAQuery jpaQuery = new JPAQuery(em);
  PathBuilder<Organization> qOrganization = new PathBuilder<Organization>(Organization.class, 
            Introspector.decapitalize(Organization.class.getSimpleName()));
  return jpaQuery.from(qOrganization).count();
}
unexpected token error in hibernate with Java

unexpected token error in hibernate with Java


By : amol
Date : March 29 2020, 07:55 AM
wish helps you End is a reserved keyword so you either escape it or use table alias in select
code :
"select r.routeID, r.routeNo, r.start, r.end from Route r"
Hibernate error message: unexpected token: NULLS (error in script file line: 13 unexpected token: NULLS)

Hibernate error message: unexpected token: NULLS (error in script file line: 13 unexpected token: NULLS)


By : pinned
Date : March 29 2020, 07:55 AM
wish of those help The problem was in the database.script file. The following lines were added to the script when I added a player table (this must have been automatic because I have not touched this file):
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