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Why Pycurl returns FAILED


Why Pycurl returns FAILED

By : user2948013
Date : November 14 2020, 04:48 PM
To fix the issue you can do Well, it turns out, pycurl in windows, and pycurl in Linux just somehow different inside. So, I rewrote my code using requests library and now it works perfectly.
code :


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what's the difference between pycurl.WRITEFUNCTION and pycurl.WRITEDATA?

what's the difference between pycurl.WRITEFUNCTION and pycurl.WRITEDATA?


By : behzad
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further With the WRITEDATA callback option, you can control which file the default WRITEFUNCTION callback writes to.
The function set with the WRITEFUNCTION option is the one which is actually called as soon as there is data received that needs to be saved.
PyCurl 7.19.0: get cookies from response using getinfo(pycurl.COOKIELIST)

PyCurl 7.19.0: get cookies from response using getinfo(pycurl.COOKIELIST)


By : Laurence Rimington
Date : March 29 2020, 07:55 AM
seems to work fine There's no method to get response cookies after calling perform(). Headers sent by the server can be captured using a callback function passed to the PyCurl instance while configuring with setopt():
code :
   Callback for writing received headers. See CURLOPT_HEADERFUNCTION 
    set_cookies = []

    # closure to capture Set-Cookie
    def _write_header(header):
        match = re.match("^Set-Cookie: (.*)$", header)

        if match:
            set_cookies.append(match.group(1))

    # use closure to collect cookies sent from the server
    c.setopt(pycurl.HEADERFUNCTION, _write_header)
from curl to pycurl - how to make a mutli-part post - works with curl, fails with 422 with pycurl

from curl to pycurl - how to make a mutli-part post - works with curl, fails with 422 with pycurl


By : user2011353
Date : March 29 2020, 07:55 AM
Any of those help Figured it out.
Instead of separate setopt calls for the form data, like this
code :
c.setopt(c.HTTPPOST, [('package[package_file]', (c.FORM_FILE, '/tmp/myfile.bin'))])
c.setopt(c.HTTPPOST, [('package[distro_version_id]',  '1')])
data = [
    ('package[distro_version_id]', '1'),
    ('package[package_file]', (
        c.FORM_FILE, '/tmp/myfile.bin,
        c.FORM_CONTENTTYPE, 'application/octet-stream'
    ))]
c.setopt(c.HTTPPOST, data)
Downloading data using PycURL in Canopy under mac os High Sierra failed

Downloading data using PycURL in Canopy under mac os High Sierra failed


By : Chris
Date : March 29 2020, 07:55 AM
hop of those help? Sorry, we do not currently build libcurl with SSL support. You could use another python package (for example requests) which does support SSL.
Pycurl and io.StringIO - pycurl.error: (23, 'Failed writing body)

Pycurl and io.StringIO - pycurl.error: (23, 'Failed writing body)


By : Yassin Arrad
Date : March 29 2020, 07:55 AM
To fix the issue you can do I believe the problem is that pycurl no longer functions with StringIO like desired. A solution is to use io.BytesIO instead. You can then get information written into the buffer and decode it into a string.
Using BytesIO with pycurl instead of StringIO:
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