I am trying to do a while loop with a string conditional statement in C#

» chash » I am trying to do a while loop with a string conditional statement in C#

By : Zhou Qingwu

Date : November 28 2020, 01:01 AM

this will help I can not get rid of the error and I don't really understand what is happening. , try this:

code :

static void Main(string[] args)
    {

        string test = "";

        while (!test[1].Equals('r'))
        {
            var privateKey = new Key(); // generate a random private key
            var publicKey = privateKey.PubKey;
            var Address_testnet = publicKey.GetAddress(Network.TestNet);
            test = Convert.ToString(Address_testnet); 
        }

        Console.WriteLine("public address is {0}", test);

    }

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Conditional for loop in R not recognizing conditional statement?

By : user6832338

Date : March 29 2020, 07:55 AM

I wish this help you You're not outputting correctly. Run this version and see the comparisons happening in place. Comment out the message() once you are satisfied that everything is working correctly.

code :

library(RecordLinkage)

df <- structure(c("1", "1", "2", "2", "3", "4", "4", "4", "5", "6", 
"1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "string1", 
"str2ing", "3string", "string6", "s7ring", "string8", "string9", 
"string10", "string1", "str2ing"), .Dim = c(10L, 3L), .Dimnames = list(
    NULL, c("doc_id", "text_id", "text")))

result <- matrix(ncol = 10, nrow = 10)
# nrow() and ncol() are more elegant ways of getting row/column counts.
for(j in 1:nrow(df)) {
    for(i in 1:nrow(df)) {
        message(sprintf("comparing i=%s (%s), j=%s (%s)\n", j, df[i, 1], i, df[j, 1]))
        if(identical(df[i, 1], df[j, 1])) {
            result[i, j] <- levenshteinDist(df[j, 3], df[i, 3])
        } else {
            result[i, j] <- "Not Compared"
        }
           # printing inside the inner for loop
        print(result[i, j])
    }

}

Why does isNumeric(string) crash in a while loop with a compound conditional statement?

By : jatingupte

Date : March 29 2020, 07:55 AM

fixed the issue. Will look into that further Or does not short-circuit. Neither does And
OrElse does short-circuit (as well as AndAlso). See OrElse Operator (Visual Basic)

code :

While IsNumeric(decTemperature) = False OrElse _
      (Convert.ToDecimal(decTemperature) <= 0.0 OrElse _
       Convert.ToDecimal(decTemperature) > 135.0)

How to create if conditional statement from string within javascript for loop without using eval()

By : user2403436

Date : March 29 2020, 07:55 AM

wish helps you Javascript Arrays have a function called filter which can be used to do things like you want to achieve.
For example you have an array with numbers:

code :

 var your_data_array = [
 { 
       name: "Kendall Jackson Vintner's Chardonnay",
        appellation: "",
        country: "United States",
        price: "14.99",
        primarygrape: "Chardonnay",
        qty: "35",
        region: "California",
        regprice: "18.99",
        sku: "345",
        vintage: "2016" },
        { 
       name: "Kendall Jackson Vintner's Chardonnay",
        appellation: "",
        country: "United States",
        price: "14.99",
        primarygrape: "Chardonnay",
        qty: "35",
        region: "California",
        regprice: "18.99",
        sku: "345",
        vintage: "2016" },
        { 
       name: "Kendall Jackson Vintner's Chardonnay",
        appellation: "",
        country: "United States",
        price: "14.99",
        primarygrape: "Chardonnay",
        qty: "35",
        region: "California",
        regprice: "18.99",
        sku: "345",
        vintage: "2016" }
 ]
 
 var filtered_array = your_data_array.filter(function(dataElement) {
   return dataElement.country == "United States";
 })
 
 console.log(filtered_array)

Python partitioning string list by using for loop conditional statement

By : kamatchinathan

Date : March 29 2020, 07:55 AM

around this issue You can use split() method . I updated all you can try and check it now.

code :

my_list = ['Say Hello to Python', 'Say Hi to HiPython', 'Goodbye Python']
for i in range(len(my_list)):
    if 'Hello' in my_list[i]:
        delete = 'Hello'
        get = my_list[i].split(delete, 1)[0]
        my_list[i] = get
    if 'Hi' in my_list[i]:
        delete = 'Hi'
        get = my_list[i].split(delete, 1)[0]
        my_list[i] = get


print(my_list)