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Why does C# also not allow empty conditions in while loops?


Why does C# also not allow empty conditions in while loops?

By : David Möller
Date : December 01 2020, 04:55 PM
around this issue
After all my research I can only conclude that the while loop's inability to accept empty expressions is illogical.
code :


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Java efficiency comparison: 2 Loops with 2 conditions VS 1 Loop with 4 conditions

Java efficiency comparison: 2 Loops with 2 conditions VS 1 Loop with 4 conditions


By : Gurpreet singh
Date : March 29 2020, 07:55 AM
Hope that helps My intuition is that the version of the code with one loop should be faster than the version with two loops. (Assuming that you correct the syntax errors first!) I doubt that the optimizer would be able to combine the two loops into one, and performing the list iteration twice is going to take longer than performing it once.
However, my advice to you would be:
Two for loops for with some conditions

Two for loops for with some conditions


By : cornie
Date : March 29 2020, 07:55 AM
I wish did fix the issue. This might give you some ideas, though I'm sure it's not 100% correct for your specific use case because the code you posted is sort of unclear. But you should be able to adapt this to your needs.
code :
result = []
for ii, term in enumerate(idf):
    result.append(0)
        for tf in tf_ar[6*ii:6*(ii+1)]:
            result[-1] += term * tf
Using while loops and if conditions

Using while loops and if conditions


By : Bismark Castilla Mon
Date : March 29 2020, 07:55 AM
To fix this issue Actually if you had you tested out your code snippet (which was fairly close) you would have got it working in a couple of iterations.
Here is a fully tested code snippet that works as per problem statement:
code :
    public static void main(String[] args) 
    {
        // TODO Auto-generated method stub
        String name = "rania";
        String endString = "xyz";
        Scanner input= new Scanner(System.in);

        String aString =input.next();

        // Assume name will not be found6
        Boolean isNameFound = false;

        while(!aString.equals(endString))
        {   
            if (aString.equals(name))
            {
                isNameFound = true;
                // This is to ensure program does not quit when the name is found
                // break;  
            }

            aString = input.next();
        }


        if(isNameFound)
        {
            System.out.println("My name FOUND");
        }
        else
        {
            System.out.println("My name NOT FOUND");
        }
    }
sjhsa
sdkhfds
khds;kuf
xyz
My name NOT FOUND
afkhds
kjfdsgaks
fdgkjfd
gvkjfd
rania
My name FOUND
Python loops with conditions

Python loops with conditions


By : Vicky
Date : March 29 2020, 07:55 AM
I wish this help you You can use itertools.islice(iterable,start,stop[,step]) for that:
code :
from itertools import islice

def f(array):
    for (i, row) in islice(enumerate(array),some_number):
        for (j, value) in islice(enumerate(row),some_other_number+1,None):
            # do_something
            pass
from itertools import islice

def f(array):
    for row in islice(array,some_number):
        for value in islice(row,some_other_number+1,None):
            # do_something
            pass
I can't get past a few do-while loops even though their conditions have not been met

I can't get past a few do-while loops even though their conditions have not been met


By : user3701018
Date : March 29 2020, 07:55 AM
This might help you You are telling the user that they entered wrong input and ask them the enter input again before you check the condition:
code :
do
{
    std::cout<<"The first integer must be smaller than the second integer. Please enter two integers.\n";
    std::cin>>x>>y;

} while (x>y);
int x = 0;   // important !! initialize your variables !! always !!
int y = 0;   // important !! initialize your variables !! always !!
while ( x > y) 
{
    std::cout<<"The first integer must be smaller than the second integer. Please enter two integers.\n";
    std::cin>>x>>y;

}
// do not read any input from user before this loop
do {
   std::cout << "please enter two numbers x,y such that 0<x<y<100";
   std::cin >> x >> y;
} while ( x > y || x < 0 || y > 100);
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