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How to save a FirstName of a Person efficiently without duplicate entries


How to save a FirstName of a Person efficiently without duplicate entries

By : Menna Hamedo
Date : December 01 2020, 04:55 PM
will help you You are looking for an extreme form of normalisation that I would classify as micro-optimisation. Most databases I know of do not go that far, but why not after all.
This can be simply achieved by creating a firstname table that holds all known first names in your database. Then replace your firstname column in your main table by a foreign key reference to this table (typically, a 4-byte INT).
code :


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Which algorithm for hashing name, firstName and birth-date of a person

Which algorithm for hashing name, firstName and birth-date of a person


By : user2954258
Date : March 29 2020, 07:55 AM
should help you out If you want to search for a person knowing only those credentials, you could store the SHA-1 in the database(or MD5 for speed, unless you have like a quadrillion people to sample).
The hash will be worthless, as it stores no information about the person, but it can work for searching a database. You just want to make sure that the three pieces of information match, so it would be safe to just concatenate them:
code :
user.hash = SHA1(user.firstName + user.DOB + user.lastName)
hash = SHA1(query.firstName + query.DOB + query.lastName)

for user in database:
  if user.hash == hash:
    return user
                          1
---------------------------------------------------
340,282,366,920,938,463,463,374,607,431,768,211,456
0.0000000000000000000000000000000000000293873 %
Efficent way to sort 'Person.firstName' under first alphabetically letter

Efficent way to sort 'Person.firstName' under first alphabetically letter


By : user7873777
Date : March 29 2020, 07:55 AM
hop of those help? I iterate through a long list of names, which I assign each to a 'Person' object. A Person object has a firstName and a lastName. I am looking for a efficent way to sort all the firstNames beginning with the letter A through Z. I have come up with this solutions but it is not efficent, or there is surely an easier way than creating '24' arrays for each letter of the alphabet. , You could do something like this:
code :
NSArray *names = @[@"Bob", @"Book2", @"August", @"Zulu", @"Agnoz"];
NSMutableDictionary *buckets = [[NSMutableDictionary alloc] init];
for (NSString *name in names) {
    NSString *index = [name substringToIndex:1];
    if (!buckets[index]) {
        buckets[index] = [[NSMutableArray alloc] init];
    }
    [buckets[index] addObject:name];
}
I need to get the whole row for all duplicate entries efficiently

I need to get the whole row for all duplicate entries efficiently


By : user3847257
Date : March 29 2020, 07:55 AM
like below fixes the issue internet! I'm pretty new to SQL and I need to get all the rows with duplicate information in certain fields and have them display right next to their other duplicates (group by duplicates). , I would do something like this:
code :
with cte as (
   SELECT *
      , count(*) over (partition by B, C, D, E, F, G) as cnt
      , dense_rank() over (order by B, C, D, E, F, G) as grp
   FROM STI.[dbo].[tbl_Consignee]
)
select * 
from cte
where cnt > 1
order by grp
Java QueryDSL 3.6.0 Projection.bean(Person.class, person.firstName, person.count())

Java QueryDSL 3.6.0 Projection.bean(Person.class, person.firstName, person.count())


By : Yuki taka
Date : March 29 2020, 07:55 AM
it should still fix some issue I chained .as method on top of .count to groupByCount attribute as shown below. This way I was able to avoid writing n! constructors.
code :
personRepo.getQueryDSL().createQuery(person).groupBy(person.isCitizen)
.list(Projections.bean(Alarm.class, person.isCitizen,
person.count().as(person.groupByCount));
There is no argument given that corresponds to the required formal parameter 'firstName' of 'Person.Person(string, strin

There is no argument given that corresponds to the required formal parameter 'firstName' of 'Person.Person(string, strin


By : user3535446
Date : March 29 2020, 07:55 AM
hope this fix your issue It looks like this is a typo. Because each constructor of derived type in inheritance should call base constructor implicitly or explicitly.
A constructor like this:
code :
public Employee () {}
public Employee () : base() {}
public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }

    public Person(string firstName = null, string lastName = null)
    {
        FirstName = firstName;
        LastName = lastName;
    }
}
public class Employee : Person
{
     public string DepartmentName { get; set; }
}
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