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specify fields to be serialized with JSON


specify fields to be serialized with JSON

By : Frank Holden
Date : November 29 2020, 01:01 AM
will be helpful for those in need Try ScriptIgnoreAttribute
code :


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Order of serialized fields using JSON.NET

Order of serialized fields using JSON.NET


By : Sanobar Nishat
Date : March 29 2020, 07:55 AM
wish of those help UPDATE
I just saw the downvotes. Please see the answer from 'Steve' below for how to do this.
Serialize custom exception to JSON, not all fields are serialized

Serialize custom exception to JSON, not all fields are serialized


By : mompoloki
Date : March 29 2020, 07:55 AM
Any of those help I made type and severity non-static, and it seems to be working fine. I used the following code, and I see both type and severity in the serialized output.
code :
public class MyException extends RuntimeException
{
    private String type = null;
    private String severity = null;

    public String getType() {
        return type;
    }

    public void setType(String type) {
        this.type = type;
    }

    public String getSeverity() {
        return severity;
    }

    public void setSeverity(String severity) {
        this.severity = severity;
    }

    public MyException(String message) {
        super(message);
    }
}
MyException exc = new MyException("Here goes my exception.");
exc.setType(exc.getClass().getSimpleName());    
exc.setSeverity("Major");

ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.writeValueAsString(exc));
How to add extra fields to serialized JSON of an entity

How to add extra fields to serialized JSON of an entity


By : Jupiteramoon
Date : March 29 2020, 07:55 AM
Hope this helps I found a solution using JMS. First of all, install JMS. You can find details in this URL: https://jmsyst.com/libs/serializer
After that, modify the class like this;
code :
/**
 * @ORM\Table(name="sample_table")
 */
class UserTable
{
    /**
     * @ORM\Column(type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $id;

    /**
     * @ORM\Column(type="string")
     */
    private $userName;

    /**
     * @ORM\Column(type="string", nullable=true)
     */
    private $fullName;

    ...

    /**
     * @VirtualProperty
     * @SerializedName("extraField")
     * @return string
     */
    public function getExtraField(){
        return "EXTRA_FIELD";
    }

}
$serializer = SerializerBuilder::create()->build();
$jsonContent = $serializer->serialize($user, 'json');

return new JsonResponse($jsonContent, 200, array(), true);
Specify class fields to be serialized to JSON in Ktor

Specify class fields to be serialized to JSON in Ktor


By : user2880906
Date : March 29 2020, 07:55 AM
it should still fix some issue Using Gson, you have a couple of options to the best of my knowledge.
1. Using Transient
code :
data class Foo(
    @Transient val a: Int,
    val b: Int)
val gson = GsonBuilder()
    .excludeFieldsWithoutExposeAnnotation()
    .create();
data class Foo(
    val a: Int,
    @Expose val b: Int)
val gson = GsonBuilder()
    .addSerializationExclusionStrategy(strategyInstance)
    .create();
object : ExclusionStrategy() {
  override fun shouldSkipField(field: FieldAttributes): Boolean {
  }

  override fun shouldSkipClass(clazz: Class<*>): Boolean {
  }
}
C# Serialized JSON object cannot map to destination fields for POST

C# Serialized JSON object cannot map to destination fields for POST


By : dtrcode
Date : March 29 2020, 07:55 AM
hope this fix your issue Hi I would like to figure out how once an object is serialized how to map the fields in the POST API model? , This solves your problem.
code :
List<ProductSQL> myObjectList = new List<ProductSQL>();
using (SqlCommand command = new SqlCommand(query, connection))
{
    connection.Open();
    var reader = command.ExecuteReader();
    if (reader.HasRows)
    {
        while (reader.Read())
        {
            ProductSQL myObject = new ProductSQL();
            myObject.sku = reader["sku"].ToString();  
            myObject.description = reader["description"].ToString();
            myObjectList.Add(myObject);
        }
    }
    var JsonResult = JsonConvert.SerializeObject(myObjectList);
    Console.WriteLine(JsonResult);
}


/* Program Initialization Now need to map the products to their respective fields from the SQL Database to the API*/

Console.WriteLine("Post Articles To API");
HttpResponseMessage response2;
foreach(ProductSQL product in myObjectList.ToList())
{
    Product NewProduct = new Product();
    NewProduct.sku = product.sku;
    NewProduct.title = product.title;
    NewProduct.description =product.description;
}
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