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How to make sure the constructor is executed when I'm trying to reach a static property?


How to make sure the constructor is executed when I'm trying to reach a static property?

By : Rekha
Date : November 25 2020, 01:01 AM
this one helps. I think you should read up on OOP basics. Your class has some major mistakes in it.
First of all, your constructor will not set $email, $role, or $active. You declared those fields as static. Static fields can only be accessed from a static context. The constructor is not a static context.
code :


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how to call constructor from static constructor in c# so that normal constructor is executed first

how to call constructor from static constructor in c# so that normal constructor is executed first


By : Hitesh Swami
Date : March 29 2020, 07:55 AM
hope this fix your issue The static constructor will start executing before the instance constructor, but you can still call the instance constructor... and indeed this is a common approach for implementing a singleton. For example:
code :
public sealed class Singleton
{
    // I'd usually make it a property in real code, backed by a readonly field
    public static readonly Singleton Instance;

    static Singleton()
    {
        Instance = new Singleton();
    }

    private Singleton()
    {
        // Only invoked from the static constructor
    }
}
Why does it seem as if my static constructor is only executed once?

Why does it seem as if my static constructor is only executed once?


By : Balasundaram B
Date : March 29 2020, 07:55 AM
hope this fix your issue Because the static constructor is executed only once.
From C# Specification:
When objects created with static reference, why do instance block & default constructor get executed before static b

When objects created with static reference, why do instance block & default constructor get executed before static b


By : V.K
Date : March 29 2020, 07:55 AM
wish helps you Ok. static fields / blocks are set / executed during class initialization. They are executed in the order that they appear in the code. So, after class TestLab is loaded, when it is getting initialized, the following things happen :
Static block is not executed before constructor

Static block is not executed before constructor


By : joalan
Date : March 29 2020, 07:55 AM
Any of those help Static members of a class are not instance members. That means that they are attached (bound) to the class itself and not to the instances of the class. Here you have 4 instances of the TeacherEx class, but that does not matter for the static members. You can access static members even if you don't have any instances of the class.
Try it yourself:
code :
public static void main(String[] args) {

    println(TeacherEx.t.toString());

}
Why the default constructor executed before the static constructor?

Why the default constructor executed before the static constructor?


By : kaushik shaw
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Depending on Microsoft
code :
class SimpleClass
{
    // Static variable that must be initialized at run time.
    static readonly long baseline;

    // Static constructor is called at most one time, before any
    // instance constructor is invoked or member is accessed.
    static SimpleClass()
    {
        baseline = DateTime.Now.Ticks;
    }
}
private class Single
{
    private static readonly Single s;
    static Single()
    {
        Console.WriteLine("static");
        s = new Single();
    }
}
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