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Python lists get specific length of elements from index


Python lists get specific length of elements from index

By : SHHHHHme
Date : November 24 2020, 03:41 PM
it should still fix some issue , You are actually very close:
code :


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How to slice lists in Python based on the length of its elements

How to slice lists in Python based on the length of its elements


By : Suresh Nookala
Date : March 29 2020, 07:55 AM
To fix this issue How to slice a list based on the length of its elements? For example, how do I turn , You can try this:
code :
l = ['A', 'E', 'LA', 'ELA', 'B', 'CD']

maximum = max([len(i) for i in l])
minimum = min([len(i) for i in l])
l = list([i for i in l if len(i)==s] for s in range(minimum, maximum+1))
print(l)
[['A', 'E', 'B'], ['LA', 'CD'], ['ELA']]
Merge Two Scala Lists of Same Length, With Elements At Same Index Becoming One Element

Merge Two Scala Lists of Same Length, With Elements At Same Index Becoming One Element


By : Jamela314
Date : March 29 2020, 07:55 AM
it helps some times I have two Scala lists with the same number and type of elements, like so: , Combine zip and map:
code :
x zip y map { case (a, b) => a + b }
x zip y map (_.productIterator.mkString)
How can I compare elements in 2 lists in the same index in their respective lists in Python?

How can I compare elements in 2 lists in the same index in their respective lists in Python?


By : user3444400
Date : March 29 2020, 07:55 AM
may help you . Say I have 2 lists , simplest method would probably just be doing a list comprehension:
code :
c = [x for x,y in zip(a,b) if x == y]
from itertools import compress
mask = [x==y for x,y in zip(a,b)]
c = list(compress(a,mask))
import numpy as np
a,b = np.array(a), np.array(b)
c = a[np.equal(a,b)].tolist()
[1, 2, 7, 1]
Python creating a new list that contains elements not equal to elements of the same index of two other lists

Python creating a new list that contains elements not equal to elements of the same index of two other lists


By : virtualyyours
Date : March 29 2020, 07:55 AM
Hope this helps I am trying to create a list by iterating through a two other lists using a list comprehension and only leaving integers in the list that are not equal to the same index element of the other two lists. , You could do something like this:
code :
import random
random.seed(42)

list_1 = [0,3,2,5,7,2,3,5,9,2]
list_2 = [1,7,2,5,0,0,2,3,0,4]

n = 10
pool = set(range(n))

result = [random.sample(pool - set(t), 1)[0] for t in zip(list_1, list_2)]
print(result)
[3, 0, 5, 3, 4, 4, 1, 1, 7, 0]
result = [random.choice(list(pool - set(t))) for t in zip(list_1, list_2)]
In python, how to compare two lists: same length and could have duplicate elements

In python, how to compare two lists: same length and could have duplicate elements


By : unknow
Date : September 18 2020, 12:00 AM
will help you Say I have a = [1,1,3,4] and b = [3,1,4,1] and I want a results matched. If different length or some elements are different, then return unmatched , If you don't care about the order of elements you can do this:
code :
def compare(a, b):
    return 'matched' if sorted(a) == sorted(b) else 'unmatched'

a = [1,1,3,4]
b = [3,1,4,1]
print(compare(a, b))

>>> 'matched'
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